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timofeeve [1]
2 years ago
12

The Jones family hiked 46 miles in 6 days if they hiked the same number of miles each day how many miles did they home each day

Mathematics
1 answer:
densk [106]2 years ago
7 0

Answer: Can I get brainliest? Thanks!

46/6 = x/1

46/6 = 23/3 = 7(2/3)

They hiked 7(2/3) miles each day

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A manager of a grocery store wants to determine if consumers are spending more than the national average. The national average i
strojnjashka [21]

The valid conclusions for the manager based on the considered test is given by: Option

<h3>When do we perform one sample z-test?</h3>

One sample z-test is performed if the sample size is large enough (n  > 30) and we want to know if the sample comes from the specific population.

For this case, we're specified that:

  • Population mean = \mu = $150
  • Population standard deviation = \sigma = $30.20
  • Sample mean = \overline{x} = $160
  • Sample size = n = 40 > 30
  • Level of significance = \alpha = 2.5% = 0.025
  • We want to determine if the average customer spends more in his store than the national average.

Forming hypotheses:

  • Null Hypothesis: Nullifies what we're trying to determine. Assumes that the average customer doesn't spend more in the store than the national average. Symbolically, we get: H_0: \mu_0 \leq \mu = 150
  • Alternate hypothesis: Assumes that customer spends more in his store than the national average. Symbolically H_1: \mu_0 > \mu = 150

where \mu_0 is the hypothesized population mean of the money his customer spends in his store.

The z-test statistic we get is:

z = \dfrac{\overline{x} - \mu_0}{\sigma/\sqrt{n}} = \dfrac{160 - 150}{30.20/\sqrt{40}} \approx 2.094

The test is single tailed, (right tailed).

The critical value of z at level of significance 0.025 is 1.96

Since we've got 2.904 > 1.96, so we reject the null hypothesis.

(as for right tailed test, we reject null hypothesis if the test statistic is > critical value).

Thus, we accept the alternate hypothesis that customer spends more in his store than the national average.

Learn more about one-sample z-test here:

brainly.com/question/21477856

3 0
1 year ago
Read 2 more answers
The Bernards are trying to determine their babysitter's rates but are to embarrassed to just ask her. They were charged $20 for
Alina [70]

Answer:

A = 5.5t + 9

Step-by-step explanation:

We assume that the relationship between t and A is linear.

We have two points on a line: (2, 20) and (4, 31).

We now find the equation of the line.

A = mt + b

m = (31 - 20)/(4 - 2) = 11/2 = 5.5

20 = 5.5(2) + b

20 = 11 + b

b = 9

A = 5.5t + 9

3 0
3 years ago
In a shelter 15% of the animals are puppies, 45% are cats, and the rest are adult dogs. Based on this information ,if there are
frozen [14]
20 is the answer.

15% of 50= 7.5
45% of 50= 22.5
22.5+7.5=30
50-30=20.
7 0
2 years ago
Finch divides 12 peaches and 18 Nectarines into the same number of equal groups. How many possible groups of each fruit can he m
Naya [18.7K]

This question is based on prime factorization method.

As given there are 12 peaches and 18 nectarines

Factors of 12 are : 2,3,4,6 and 12

Factors of 18 are : 2,3,6,9 and 18

As mentioned, fruits are divided into the same number of equal groups, so the groups can be formed as-

1. 6 groups of peaches with 2 in each and 6 groups of nectarines with 3 in each,

2. 3 groups of peaches with 4 in each and 3 groups of nectarines with 6 in each.

3. 2 groups of peaches with 6 in each and 2 groups of nectarines with 9 in each.




7 0
2 years ago
Explain how you would use estimation to help solve this problem. Be sure to include the number sentence you would
Harman [31]
I’m not sure what your teacher wants you to do but I would do 110-50=60
7 0
3 years ago
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