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soldi70 [24.7K]
3 years ago
9

Which one on these natural resources is nonrenewable?

Mathematics
2 answers:
wlad13 [49]3 years ago
6 0

Answer:

B.) I think it is B because sunlight is renewable, so is corn and sugarcane. Which leaves the odd one out.

ladessa [460]3 years ago
4 0

Answer:

b. oil or petroleum

Step-by-step explanation:

it's a natural resource that can run out

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What is the value of x in the equation 3x − 5 = x + 7?
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6

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You are the manager of a donut shop. Presently, you sell your donuts for $1.00 each and everyday you sell 500 donuts. However, y
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Answer:<u> </u><u>$1.75</u>

Solve for:

What price would result in the most revenue?

Step-by-step explanation:

Let the price of one donut = 1 + 0.05x

Let the # of donuts he can sell = 500 - 10x

Revenue,

R(x) = (1 + 0.05x)(500 - 10x)

R(x) = 500 - 10x + 25x - 0.5x^2

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Revenue is maxed when x = 15

When the revenue is maxed,

Price = 1 + 0.05(15)\\=1 + 0.75\\=1.75

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2 years ago
PLEASE HELP<br> A. 7 inches<br> B. 14 inches<br> C. 49 inches<br> D. 28 inches
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Answer:

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Step-by-step explanation:

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3 years ago
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Independent random samples taken on two university campuses revealed the following information concerning the average amount of
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Answer:

p_v =P(t_{88}>6.960) =2.91x10^{-10}

So with the p value obtained and using the significance level given \alpha=0.05 we have p_v so we can conclude that we have enough evidence to reject the null hypothesis, and we can said that at 5% of significance the mean of the group A is significantly lower than the mean for the group B.  

Step-by-step explanation:

The statistic to test the hypothesis is given by this formula:

t=\frac{(\bar X_A-\bar X_B)-(\mu_{A}-\mu_B)}{\sqrt{\frac{s_A^2}{n_A}}+\frac{s_B^2}{n_B}}

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Alternative hypothesis: \mu_A >\mu_B

Or equivalently:

Null hypothesis: \mu_A - \mu_B \leq 0

Alternative hypothesis: \mu_A -\mu_B>0

Our notation on this case :

n_A =50 represent the sample size for group A

n_B =40 represent the sample size for group B

\bar X_A =280 represent the sample mean for the group A

\bar X_B =250 represent the sample mean for the group B

s_A=20 represent the sample standard deviation for group A

s_B=23 represent the sample standard deviation for group B

And now we can calculate the statistic:

t=\frac{(280 -250)-(0)}{\sqrt{\frac{20^2}{50}}+\frac{23^2}{40}}=6.511

Now we can calculate the degrees of freedom given by:

df=50+40-2=88

And now we can calculate the p value using the alternative hypothesis:

p_v =P(t_{88}>6.960) =2.91x10^{-10}

So with the p value obtained and using the significance level given \alpha=0.05 we have p_v so we can conclude that we have enough evidence to reject the null hypothesis, and we can said that at 5% of significance the mean of the group A is significantly lower than the mean for the group B.  

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Step-by-step explanation:

hope this helps!

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