You wrote it there yourself, at the beginning of your question.
You wrote E = I x R
Divide each side by ' I ' : E / I = R
That's what you're asking for. ^
Answer:
a) 1.8 × 10^-12 cm³ or 1.8 × 10^-12 cubic meters
b) 7.1 × 10^-6 mm² or 7.1 × 10^-6 square millimeters
Step-by-step explanation:
a) We are assuming that the shape of the bacteria is a sphere.
Hence, Volume of the Sphere(Bacteria) = 4/3 × π × r³
Diameter = 1.5 μm
Radius = Diameter/2 = 1.5μm/2
= 0.75μm
We are told that the volume should be in cubic centimeters
Converting 0.75μm to centimeters
1 μm = 1 × 10^-4 cm
0.75 μm =
Cross Multiply
= 0.75 μm × 1 × 10^-4 cm/ 1 μm
= 0.000075cm
Volume of the Sphere(Bacteria) = 4/3 × π × r³
= 4/3 × π × (0.000075)³
= 1.767145867 × 10^-12 cm³
Approximately as 2 significant figures = 1.8 × 10^-12 cm³
b) The formula for the Surface area of a Sphere = 4πr²
Diameter = 1.5 μm
Radius = Diameter/2 = 1.5μm/2
= 0.75μm
We are told that the surface area should be in square millimeters
Converting 0.75μm to millimeters
1 μm = 0.001 mm
0.75 μm =
Cross Multiply
= 0.75 μm ×0.001mm/ 1 μm
= 0.00075mm
Surface Area of a Sphere
= 4 × π × r²
= 4 × π × 0.00075²
= 7.06858 ×10^-6 mm²
Approximately to 2 significant figures
= 7.1 × 10^-6 mm²
Answer:
x² - 4x + 12
Step-by-step explanation:
x=2+2.82843i
x=2−2.82843i
Answer:
20 square feet
Step-by-step explanation:
The length of a rectangular deck is five times it's width if the decks perimeter is 24 feet what is the decks area
Step 1
We find the Length and Width of the deck
Perimeter of a rectangle = 2L + 2W
The length of a rectangular deck is five times it's width
W = Width
L = Length = 5W
P = 24 feet
Perimeter = 2(5W) + 2W
24 = 10W + 2W
24 = 12 W
W = 24/12
W = 2 feet
Solving for L
L = 5W
L = 5 × 2 feet
L = 10 feet
Step 2
We find the area of the deck
Area of the deck(Rectangle) = Length × Width
= 10 feet × 2 feet
= 20 square feet
Answer:
Step-by-step explanation:
a= 2qr^3 quotent 6p^2