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3 years ago

Simplify: −z3+5k6−(−z3+10k6)

Mathematics

2 answers:

natta225 [31]3 years ago

7 0

Answer:

The answer to your question is -5k⁶

Step-by-step explanation:

Polynomial

- z³ + 5k⁶ - (-z³ + 10k⁶)

Use law of signs for the parenthesis

- z³ + 5k⁶ + z³ - 10k⁶

Use associative property for like terms

(-z³ + z³) + (5k⁶ - 10k⁶)

Simplify like terms

(0) + (-5k⁶)

Result

-5k⁶

Likurg_2 [28]3 years ago

4 0

Answer:

-5k ^6 is your answer! Hope this helps!

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The depth of water at a dock can be modeled as y = 3 sin (7x) + 7. At

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Answer:C

Step-by-step explanation:

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3 years ago

Solve the inequality: -7y - 3x < 21

SashulF [63]

Answer:

x> -7/3y -7

Step-by-step explanation: -7y-3x<21

Step 1: Add 7y to both sides.

−3x−7y+7y<21+7y

−3x<7y+21

Step 2: Divide both sides by -3.

-3x/-3 < 7y+21/-3

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3 years ago

5^(-x)+7=2x+4 This was on plato

Setler79 [48]

Answer:

Below

I hope its not too complicated

$x=\frac{\text{W}_0\left(\frac{\ln \left(5\right)}{2e^{\frac{3\ln \left(5\right)}{2}}}\right)}{\ln \left(5\right)}+\frac{3}{2}$

Step-by-step explanation:

$5^{\left(-x\right)}+7=2x+4\\\\\mathrm{Prepare}\:5^{\left(-x\right)}+7=2x+4\:\mathrm{for\:Lambert\:form}:\quad 1=\left(2x-3\right)e^{\ln \left(5\right)x}\\\\\mathrm{Rewrite\:the\:equation\:with\:}\\\left(x-\frac{3}{2}\right)\ln \left(5\right)=u\mathrm{\:and\:}x=\frac{u}{\ln \left(5\right)}+\frac{3}{2}\\\\1=\left(2\left(\frac{u}{\ln \left(5\right)}+\frac{3}{2}\right)-3\right)e^{\ln \left(5\right)\left(\frac{u}{\ln \left(5\right)}+\frac{3}{2}\right)}$

$Simplify\\\\\mathrm{Rewrite}\:1=\frac{2e^{u+\frac{3}{2}\ln \left(5\right)}u}{\ln \left(5\right)}\:\\\\\mathrm{in\:Lambert\:form}:\quad \frac{e^{\frac{2u+3\ln \left(5\right)}{2}}u}{e^{\frac{3\ln \left(5\right)}{2}}}=\frac{\ln \left(5\right)}{2e^{\frac{3\ln \left(5\right)}{2}}}$

$\mathrm{Solve\:}\:\frac{e^{\frac{2u+3\ln \left(5\right)}{2}}u}{e^{\frac{3\ln \left(5\right)}{2}}}=\frac{\ln \left(5\right)}{2e^{\frac{3\ln \left(5\right)}{2}}}:\quad u=\text{W}_0\left(\frac{\ln \left(5\right)}{2e^{\frac{3\ln \left(5\right)}{2}}}\right)\\\\\mathrm{Substitute\:back}\:u=\left(x-\frac{3}{2}\right)\ln \left(5\right),\:\mathrm{solve\:for}\:x$

$\mathrm{Solve\:}\:\left(x-\frac{3}{2}\right)\ln \left(5\right)=\text{W}_0\left(\frac{\ln \left(5\right)}{2e^{\frac{3\ln \left(5\right)}{2}}}\right):\\\quad x=\frac{\text{W}_0\left(\frac{\ln \left(5\right)}{2e^{\frac{3\ln \left(5\right)}{2}}}\right)}{\ln \left(5\right)}+\frac{3}{2}$

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3 years ago

How can the logarithmic expression be rewritten?

andrey2020 [161]

False
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I think?

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3 years ago

What is the value of (-14⁰)-2<br> a -1/196<br> b 1/196<br>c 0 <br>d 1

natta225 [31]

Answer:

It is -1/196 for those who want the quick answer and not the one below me calling the person dumb which I reported BTW because it is unacceptable.

Step-by-step explanation:

I know i dont work for Brainly but i apologize for the person who was called dumb.

6 0

3 years ago