The question might have some mistake since there are 2 multiplier of t. I found a similar question as follows:
The population P(t) of a culture of bacteria is given by P(t) = –1710t^2+ 92,000t + 10,000, where t is the time in hours since the culture was started. Determine the time at which the population is at a maximum. Round to the nearest hour.
Answer:
27 hours
Step-by-step explanation:
Equation of population P(t) = –1710t^2+ 92,000t + 10,000
Find the derivative of the function to find the critical value
dP/dt = -2(1710)t + 92000
= -3420t + 92000
Find the critical value by equating dP/dt = 0
-3420t + 92000 = 0
92000 = 3420t
t = 92000/3420 = 26.90
Check if it really have max value through 2nd derivative
d(dP)/dt^2 = -3420
2nd derivative is negative, hence it has maximum value
So, the time when it is maximum is 26.9 or 27 hours
Answer:
60x+147
Step-by-step explanation:
10(6x+15)-3
60x+150-3
60x+147
Answer:
Step-by-step explanation:
If slope of two lines are equal, then they are parallel lines.
If product of the slope of two lines is (-1), then they are perpendicular lines.
C) y = x + 2
Slope m1 = 1
y = -x + 3
Slope m2 = -1
m1 * m2 = 1 * (-1) = -1
These are perpendicular lines.
D) y = 3x + 2
Slope = m1 = 3
y = 3x - 2
Slope = m2 = 3
Slopes are equal. So, they are parallel lines.
E)y= 3
This line is parallel to x -axis.
x = 4
This line is parallel to y-axis.
So, both lines are perpendicular to each other.
F) y = x + 8
slope m1 = 1
y = -x + 3
Slope = m2 = -1
M1 * m2 = 1 * (-1) = -1
So, These are perpendicular lines
Answer:
y=7x-188
Step-by-step explanation:
We know that this line must have a slope of 7, because this line is parallel to y=7x+13
We must use the point slope formula: y-
= m(x-
)
Next, we will plug in the point (28,8) for and , and 7 in for m
y-8=7(x-28)
Solve the equation, first by distributing the 7
y-8=7x-196
Add the 8 over
y=7x-188
Answer:
1.5 ft^2
Step-by-step explanation:
Since the length is divided into 4 parts,
Length of a small square = 2/4
= 0.5 ft
Hence,
Area of 1 small square = (0.5)(0.5)
= 0.25 ft^2
Area of shaded portion = Area of 6 small squares
= 6(0.25)
= <u>1.5 ft^2</u>
