The "parent function" is y = (log to the base 2 of) x
The domain of this function is (0, infinity) (all real numbers greater than zero).
The range of this function is the same as above.
If you replace "x" with "x+1" in the parent function, the associated graph will look the same as that of the given function, EXCEPT that it will be translated by 1 unit to the left.
After this has happened, that "-3" will shift the entire new graph downward by 3 units.
Step-by-step explanation:
<u>a. the area of a two-dimensional composite figure</u>
In this situation, we need to draw any necessary segments to view the figure as basic shapes, then:
- Step 1: add basic shape areas belonging to the composite shape
- Step 2: subtract basic shape areas NOT belonging to the composite shape
<u>b. the surface area of a three-dimensional composite figure</u>
As we know (3D) composite objects are made of two or more objects put together. To find the surface area of a 3D composite object, we need:
- Step 1: find the outside surface area of each object
- Step 2: add the surface areas together
Hope it will find you well
System of Linear Equations entered :
[1] y - 2x/3 = -1
[2] y + x = 4
// To remove fractions, multiply equations by their respective LCD
Multiply equation [1] by 3
// Equations now take the shape:
[1] 3y - 2x = -3
[2] y + x = 4
Graphic Representation of the Equations :
-2x + 3y = -3 x + y = 4
Solve by Substitution :
// Solve equation [2] for the variable x
[2] x = -y + 4
// Plug this in for variable x in equation [1]
[1] 3y - 2•(-y +4) = -3
[1] 5y = 5
// Solve equation [1] for the variable y
[1] 5y = 5
[1] y = 1
// By now we know this much :
y = 1
x = -y+4
// Use the y value to solve for x
x = -(1)+4 = 3
I hope this help you
Answer:
see attached
Step-by-step explanation:
Here's your worksheet with the blanks filled.
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Of course, you know these log relations:
log(a^b) = b·log(a) . . . . . power property
log(a/b) = log(a) -log(b) . . . . . quotient property
log(x) = log(y) ⇔ x = y . . . . . . . . . equality property
