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12345 [234]
3 years ago
8

What is another way to represent 100

Mathematics
2 answers:
NeX [460]3 years ago
6 0

Answer:

The Roman numeral Ⅽ

Step-by-step explanation:

Monica [59]3 years ago
4 0

you \: can \: represent \: it \: as \\  {10}^{2 } \: (indices)  \\ or  \\ \: 1.0 \times   \ {10}^{2}  \\ (standard  \\ form)

Or in Roman figure as C

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-112/3 x (-4 1/5) =?
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3 years ago
Compare and contrast the solution of a-3=15 and a-3 is greater than or equal to 15.
aivan3 [116]
In a - 3 = 15, the value of a HAS to be 18.

In a - 3 is greater than or equal to 15, the value of a is any value that is 18 or higher.
7 0
3 years ago
Caleb started with 50 bacteria for his science experiment and they doubled in one day. Jenna also started with 50 bacteria for h
MrRa [10]

Answer: B

Step-by-step explanation:

The second power basically means that you multiply the number by itself that many times depending on the power, and since it's 50^2, the answer is Caleb - 100 | Jenna - 2,500. (Tip: Just multiply 50 x 50)

4 0
3 years ago
A tank contains 300 liters of fluid in which 40 grams of salt is dissolved. Brine containing 1 gram of salt per liter is then pu
bonufazy [111]

Answer:

A(t) = 300 -260e^(-t/50)

Step-by-step explanation:

The rate of change of A(t) is ...

A'(t) = 6 -6/300·A(t)

Rewriting, we have ...

A'(t) +(1/50)A(t) = 6

This has solution ...

A(t) = p + qe^-(t/50)

We need to find the values of p and q. Using the differential equation, we ahve ...

A'(t) = -q/50e^-(t/50) = 6 - (p +qe^-(t/50))/50

0 = 6 -p/50

p = 300

From the initial condition, ...

A(0) = 300 +q = 40

q = -260

So, the complete solution is ...

A(t) = 300 -260e^(-t/50)

___

The salt in the tank increases in exponentially decaying fashion from 40 grams to 300 grams with a time constant of 50 minutes.

6 0
3 years ago
Read 2 more answers
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