All categories

3 years ago

3x+2y=3y-2 line 1 x+y=10 line 2 solve for x/y

Mathematics

1 answer:

GrogVix [38]3 years ago

3 0

Answer:

x/y=1/4

Step-by-step explanation:

3x+2y=3y-2

3x=3y-2y-2

3x=y-2

y=3x+2

x+y=10

x+3x+2=10

4x+2=10

4x=10-2

4x=8

x=8/4

x=2

2+y=10

y=10-2

y=8

x/y=2/8=1/4

You might be interested in

The sides of a square are increased by a scale factor of 6. The perimeter of the smaller square is 10 ft. What is the perimeter

inn [45]

Answer:

60ft

Step-by-step explanation:

I have not done this kind of work in a while but if you scale each side of the square by 6 is should increase to a perimeter of 60ft

4 0

2 years ago

F(x)=|x+3|-1 range and domain

KiRa [710]

Hey there! :)

Answer:

Domain: (-∞, ∞)

Range: [-1, ∞)

Step-by-step explanation:

This is an absolute-value function. (Graphed below) The vertex is at (-3, -1) which consists of the minimum y-value of the function. Therefore:

Domain: (-∞, ∞)

Range: [-1, ∞)

8 0

2 years ago

Please help me!!<br> Best one gets brailiest!

brilliants [131]

<h3>Answer: 8 = g/3</h3>

Explanation:

When translating word problems into equations, the word "is" often means "equal sign"

The term quotient is the result of a division problem. So "quotient of g and 3" means "g divided by 3" or g/3.

5 0

2 years ago

Type an equation for the line shown in the graph

natulia [17]

0x+2 =y
So technically x+2=y

4 0

2 years ago

Determine what must be multiplied so that the expression below will have a common denominator. Use the backslash / to type in a

Mashutka [201]

Answer:

Multiply the first fraction by $\frac{x+4}{x+4}$

Multiply the second fraction by $\frac{x-4}{x-4}$

Step-by-step explanation:

Given

$\frac{4}{x^2 - 16} + \frac{3}{x^2 + 8x + 16}$

Required

Make the denominator equal

$\frac{4}{x^2 - 16} + \frac{3}{x^2 + 8x + 16}$

Factorize the denominator

$\frac{4}{x^2 - 4^2} + \frac{3}{x^2 + 4x + 4x+ 16}$

$\frac{4}{(x - 4)(x + 4)} + \frac{3}{(x+ 4)(x + 4)}$

Multiply the first fraction by $\frac{x+4}{x+4}$

Multiply the second fraction by $\frac{x-4}{x-4}$

$\frac{x+4}{x+4} * \frac{4}{(x - 4)(x + 4)} + \frac{3}{(x+ 4)(x + 4)} * \frac{x-4}{x-4}$

$\frac{4(x + 4)}{(x - 4)(x + 4)(x + 4)} + \frac{3(x - 4)}{(x+ 4)(x + 4)(x - 4))}$

$\frac{4(x + 4)}{(x^2 - 16)(x + 4)} + \frac{3(x - 4)}{(x^2 - 16)(x + 4))}$

<em>The expression now have the same denominator</em>

7 0

3 years ago