5/2c - 3 = 3/7c + 4...subtract 3/7c from both sides
5/2c - 3/7c - 3 = 4.....add 3 to both sides
5/2c - 3/7c = 4 + 3....common denominator of 7 and 2 is 14
35/14c - 6/14c = 7...simplify
29/14c = 7....multiply both sides by 14/29, eliminating the 29/14 on left
c = 7 * 14/29
c = 98/29 = 3 11/29
Answer:
Area = 32feet²
Step-by-step explanation:
Perimeter of a rectangule = 2(length+width)
Then:
g = 2w Eq. 1
2(g+w) = 24 Eq. 2
g = length
w = width
From Eq. 2:
(2*g + 2*w) = 24
2g + 2w = 24
2w = 24 - 2g Eq. 3
Matching Eq. 1 and Eq. 3
g = 24 - 2g
g + 2g = 24
3g = 24
g = 24/3
g = 8 feet
From Eq. 1
g = 2w
8 = 2w
8/2 = w
w = 4 feet
Check:
From Eq. 2
2(g+w) = 24
2(8+4) = 24
2*12 = 24
Answer:
Area of a rexctangle = length * width
Then:
Area = 8feet * 4feet
Area = 32feet²
Answer:
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Answer:
Step-by-step explanation:
Hence cot θ =cosθ / sinθ < 0 and sin θ < 0 that means that cos θ >0 hence θ lies on IV quadrant.
Hope this helps!