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dybincka [34]
3 years ago
9

4x = 8x − 1 x = three fourths x = 1 x = 3 x = 6

Mathematics
2 answers:
makvit [3.9K]3 years ago
5 0
Isolate the variable by subtracting 8x from both sides to get -4x = -1. multiply both sides by -1 to get 4x = 1. divide both sides by 4 to get x = 1/4.
Zielflug [23.3K]3 years ago
5 0

Answer:

x = 3

Step-by-step explanation:

Took the test

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What is the area of the rectangle?
irinina [24]

Answer:

Root square 25² - 15² = 20

Area = 20×15 = 300 cm²

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What is the surface area and volume of this figure?
andrey2020 [161]
The surface area is 16 because 10 plus6 eqals 16
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What is the solution of the system of equations ? 2x-y=7 y=2x+3
LuckyWell [14K]
<span>2x-y = 7 so y = 2x - 7
y = 2x+3

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4 0
3 years ago
A right triangle has legs of lengths 14 and 16 inches. Find the length of
Mice21 [21]

Answer:

about 21.3

Step-by-step explanation:

I found the hypotenuse value by doing the Pythagorean theorem.

a^2+b^2=c^2.

"a" and "b" are the values of the legs, and "c" is the value of the hypotenuse. So, "a" is 14 and "b" is 16.

14^2+16^2=c^2

196+256=452.

Now, I found the square root of 452. The square root of 452 is 21.26029163. This value rounded to the nearest tenth is 21.3.

In conclusion, the length of the hypotenuse rounded to the nearest tenth is 21.3 inches.

6 0
3 years ago
Given g(x) = <img src="https://tex.z-dn.net/?f=%5Cfrac%7B3%7D%7Bx%5E2%2B2x%7D" id="TexFormula1" title="\frac{3}{x^2+2x}" alt="\f
sweet [91]

We know that g(x) = \frac{3}{x^2+2x}

We have to find g^-1(x)  or inverse of g(x)

Inverse of g(x) can be determined by equating g(x) to y, and determining the value of x in terms of y

g(x) = y = \frac{3}{x^2+2x}

⇒ y × (x² + 2x) = 3

⇒ yx² + 2xy = 3

⇒ yx² + 2yx - 3 = 0

Determining the roots of x using:

x = \frac{-b + \sqrt{b^{2} - 4ac}}{2a} OR x = \frac{-b - \sqrt{b^{2} - 4ac}}{2a} , where a is coefficient of x², b is coefficient of x, and c is the constant

⇒ x = \frac{-2y + \sqrt{4y^2 - 4(2y)(-3)}}{2y} OR x = \frac{-2y - \sqrt{4y^2 - 4(2y)(-3)}}{2y}

⇒ x = \frac{-2y + \sqrt{4y^2 + 24y}}{2y} OR x = \frac{-2y - \sqrt{4y^2 + 24y}}{2y}

Hence, g^-1(x) = \frac{-2y + \sqrt{4y^2 + 24y}}{2y} OR x = \frac{-2y - \sqrt{4y^2 + 24y}}{2y}

7 0
4 years ago
Read 2 more answers
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