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Mkey [24]
2 years ago
15

7D%20" id="TexFormula1" title=" {3}^{x + 2} - {3}^{x} = \frac{8}{9} " alt=" {3}^{x + 2} - {3}^{x} = \frac{8}{9} " align="absmiddle" class="latex-formula">
Mathematics
1 answer:
ser-zykov [4K]2 years ago
6 0

3^{x + 2} - 3^{x} = 3^{x}* 3^{2} - 3^{x} = 9(3^{x}) - 1(3^{x}) = 8(3^{x})

3^{x + 2} - 3^{x} = \frac{8}{9}

⇒ 8(3^{x}) = \frac{8}{9}

⇒ 3^{x} = \frac{1}{9}   <em>multiplied both sides by 8</em>

⇒3^{x} = \frac{1}{3^{2} }

⇒ 3^{x} = 3⁻²

⇒ x = -2

Answer: x = -2

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How many complex zeros does the polynomial function have? <br><br> F(x)=2x^4 +5x^3 - x^2 +6x-1
klio [65]

Answer:

Two complex roots.

Step-by-step explanation:

F(x)=2x^4 +5x^3 - x^2 +6x-1

is a polynomial in x of degree 4.

Hence F(x) has 4 roots.  There can be 0 or 2 or 4 complex roots to this polynomial since complex roots occur in conjugate pairs.

Use remainder theorem to find the roots of the polynomial.

F(0) = -1 and F(1) = 2+5-1+6-1 = 11>0

There is a change of sign in F from 0 to 1

Thus there is a real root between 0 and 1.

Similarly by trial and error let us find other real root.

F(-3) = -1 and F(-4) = 94

SInce there is a change of sign, from -4 to -3 there exists a real root between -3 and -4.

Other two roots are complex roots since no other place F changes its sign

7 0
3 years ago
if 6th term of an ap is -10 and 10 th term is -26 then find thr 15 term​ plzzzzzzzzzzzzzzzzzzzzzzz answer i will give whatever y
Rudik [331]

Answer:

-46

Step-by-step explanation:

We need to find the common difference of this arithmetic sequence:

\frac{-26-(-10)}{10-6} =\frac{-16}{4} =-4

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a_{15}=a_6+d(15-6)=-10-4(9)=-10-36=-46

So, the 15th term is -46.

Hope this helps!

5 0
2 years ago
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greater

Step-by-step explanation:

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3 years ago
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What do you need help with?
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3 years ago
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