Question

Find the product. (-2x^2 )^3 ·3 x

Answer 1

Assignment: $\bold{Solve \ \left(-2x^2\right)^3\cdot \:3x}$

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Answer: $\boxed{\bold{-24x^7}}$

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Explanation: $\downarrow\downarrow\downarrow$

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[ Step One ] Rewrite $\bold{\left(-2x^2\right)^3}$

$\bold{-2^3\left(x^2\right)^3}$

[ Step Two ] Rewrite Equation

$\bold{-2^3\cdot \:3x^6x}$

[ Step Three ] Apply Exponent Rule

Note: $\bold{Exponent \ Rule \ \:a^b\cdot \:a^c=a^{b+c}: \ x^6x=\:x^{6+1}=\:x^7}$

$\bold{-2^3\cdot \:3x^7}$

[ Step Four ] Refine

$\bold{-24x^7}$

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$\bold{\rightarrow Rhythm \ Bot \leftarrow}$

Answer 2

( -2x^2 )^3 · 3x

( 4x )^3 · 3x

64x · 3x

192x

Hope this helped.