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romanna [79]
3 years ago
6

What is the value of b in the equation (y^-9)^b=y^45?

Mathematics
1 answer:
nevsk [136]3 years ago
5 0

Answer:

b = (log(y^45))/log(1/y^9) + (2 i π n)/log(1/y^9) for n element Z

Step-by-step explanation:

Solve for b:

(1/y^9)^b = y^45

Take the logarithm base 1/y^9 of both sides:

Answer: b = (log(y^45))/log(1/y^9) + (2 i π n)/log(1/y^9) for n element Z

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Answer:

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