Iron sulfide is the correct answer
250,826,270 lb.
or, two-hundred and fifty million, eight hundered and twenty six thousand, two-hundred and seventy pounds
To solve this problem we will use Kepler's third law of planetary motion. Formula for that law is:

Where:
T = orbital period
G = universal gravitational constant
M = mass of star
a = distance from planet to star
By rearranging this formula we get:

For Earth we have:

For Wasp-32b we have:

or
We can see that right sides are same. Left sides must be same. We can use this to solve for distance.

![\frac{365^{2}}{1.1* 2.7^{2}} = \frac{1}{a^{3} } \\ \\ 2.7^{2} =365^{2}*a^{3} \\ \\ a^{3} =\frac{2.7^{2} }{365^{2}} \\ \\ a= \sqrt[3]{\frac{2.7^{2} }{365^{2}} } \\ \\ \\ a=0.038AU](https://tex.z-dn.net/?f=%5Cfrac%7B365%5E%7B2%7D%7D%7B1.1%2A%202.7%5E%7B2%7D%7D%20%3D%20%5Cfrac%7B1%7D%7Ba%5E%7B3%7D%20%7D%20%5C%5C%20%5C%5C%202.7%5E%7B2%7D%20%3D365%5E%7B2%7D%2Aa%5E%7B3%7D%20%5C%5C%20%5C%5C%20a%5E%7B3%7D%20%3D%5Cfrac%7B2.7%5E%7B2%7D%20%7D%7B365%5E%7B2%7D%7D%20%5C%5C%20%5C%5C%20a%3D%20%5Csqrt%5B3%5D%7B%5Cfrac%7B2.7%5E%7B2%7D%20%7D%7B365%5E%7B2%7D%7D%20%7D%20%5C%5C%20%5C%5C%20%5C%5C%20a%3D0.038AU)
Wasp-32b is at distance of 0.038AU.
This is the concept of algebra, given that K is the midpoint of JL, it implies that JK=KL. Therefore formulating an equality we shall have:
JK=KL
7x+4=12x-21
this can be written as:
12x-21=7x+4
collecting like terms;
12x-7x=4+21
5x=25
dividing both sides by 5 we get:
x=5
therefore:
JK=7x+4
JK=7*5+4=39
But,
JK=LK
therefore
JL=39*2=78