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Charra [1.4K]
3 years ago
5

How are the fossil symbols and mountain belts helpful in deciding where to move the continents

Geography
1 answer:
Olegator [25]3 years ago
8 0
They allow you to see how the continents were once placed together. 
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___________ a mixture of iron and filings and sulfur will make the iron and sulfur atoms combine chemically
dusya [7]
Iron sulfide is the correct answer
3 0
3 years ago
The earth's atmosphere pushes down on the surface of the earth with a force of 14.7 lb for each square inch of the earth's surfa
bogdanovich [222]
250,826,270 lb.
or, two-hundred and fifty million, eight hundered and twenty six thousand, two-hundred and seventy pounds
4 0
3 years ago
Wasp-32b orbits with a period of only 2.7 days a star with a mass that is 1.1 times that of the sun. how many au from the star i
kaheart [24]
To solve this problem we will use Kepler's third law of planetary motion. Formula for that law is:
T^{2} = \frac{4  \pi ^{2} }{GM}  a^{3}
Where:
T = orbital period
G = universal gravitational constant
M = mass of star
a = distance from planet to star

By rearranging this formula we get:
\frac{T^{2}}{a^{3} } = \frac{4 \pi ^{2} }{GM}
For Earth we have:
\frac{365^{2}}{1^{3} } = \frac{4 \pi ^{2} }{GM}
For Wasp-32b we have:
\frac{2.7^{2}}{a^{3} } = \frac{4 \pi ^{2} }{G*1.1M} or
1.1* \frac{2.7^{2}}{a^{3} } = \frac{4 \pi ^{2} }{GM} 

We can see that right sides are same. Left sides must be same. We can use this to solve for distance.
\frac{365^{2}}{1^{3} } = 1.1* \frac{2.7^{2}}{a^{3}
\frac{365^{2}}{1.1* 2.7^{2}} = \frac{1}{a^{3} } \\ \\ 2.7^{2} =365^{2}*a^{3} \\ \\ a^{3} =\frac{2.7^{2} }{365^{2}} \\ \\ a= \sqrt[3]{\frac{2.7^{2} }{365^{2}} } \\ \\ \\ a=0.038AU

Wasp-32b is at distance of 0.038AU.
8 0
3 years ago
What has been the MOST significant cause of the decline in death rate in less developed countries?
DIA [1.3K]

Answer:

a

Explanation:

7 0
3 years ago
Point K is the midpoint of JL. If JK=7x+4 KL=12x−21, what is the length of JL? JL is units long.
lubasha [3.4K]
This is the concept of algebra, given that K is the midpoint of JL, it implies that JK=KL. Therefore formulating an equality we shall have:
JK=KL
7x+4=12x-21
this can be written as:
12x-21=7x+4
collecting like terms;
12x-7x=4+21
5x=25
dividing both sides by 5 we get:
x=5
therefore:
JK=7x+4
JK=7*5+4=39
But,
JK=LK
therefore
JL=39*2=78

5 0
4 years ago
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