Answer:
where 1 < a ≤ 9
The EXPONENT USED BY PETER is 7 in all the possible cases.
Step-by-step explanation:
Let us assume the needed number is M.
Also, given:
The needed number is GREATER than 10 Million.
⇒ M > 10 Million
⇒ M > 10,000,000
⇒ M > 
...... (1)
The needed number is SMALLER than 100 Million.
⇒ M < 100 Million
⇒ M < 100,000,000
⇒ M < 
...... (2)
Comparing (1) and (2) we can see that M can have more than 7 zeroes after 1 but LESS than 8 zeroes after 1.
So, the possible values of M can be:
where 1 < a ≤ 9
So, the EXPONENT USED BY PETER is 7 in all the possible cases.
The commutative pooperty of x + 7 is equal to 7 + x.
by the double angle identity for sine. Move everything to one side and factor out the cosine term.
Now the zero product property tells us that there are two cases where this is true,
In the first equation, cosine becomes zero whenever its argument is an odd integer multiple of
, so
where
![n[/tex ]is any integer.\\Meanwhile,\\[tex]10\sin x-3=0\implies\sin x=\dfrac3{10}](https://tex.z-dn.net/?f=n%5B%2Ftex%20%5Dis%20any%20integer.%5C%5CMeanwhile%2C%5C%5C%5Btex%5D10%5Csin%20x-3%3D0%5Cimplies%5Csin%20x%3D%5Cdfrac3%7B10%7D)
which occurs twice in the interval
for
and
. More generally, if you think of
as a point on the unit circle, this occurs whenever
also completes a full revolution about the origin. This means for any integer
, the general solution in this case would be
and
.
Answer:
maybe 4
Step-by-step explanation:
Well consider the fact a normal diet is about 1,200 calories a day. half of that is 600, there for you lose 2 pounds in a week. if you cut that in half the chances are you'll loose 4 pounds. but consuming only 300 calories a day is extremely unhealthy
