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Svetlanka [38]
2 years ago
12

Omar has a gift card for $40.00 at a gift shop. Omar wants to buy a hat for himself for $13.50. For his friends, he would like t

o buy souvenir
bracelets, which are $3.25 each. All prices include taxes.
Which inequality can be used to solve for how many bracelets Omar can buy?
ОА.
3.25x + 13.50 S 40
OB.
3.25x + 13.50 240
Oc.
13.50x +3.25 S 40
OD.
13.50x +3.25 2 40

Mathematics
2 answers:
stealth61 [152]2 years ago
6 0

Answer:

A. 3.25x + 13.50 ≤ 40

The number of bracelets is x. It's a variable.

The 13.50 is a constant.

The total needs to be less than or equal to 40 because that's all the money he has.

shutvik [7]2 years ago
3 0

Answer:

3.25x + 13.50 ≤ 40

Step-by-step explanation:

For this problem, you have to directly make the equation. Using the givens, it shows that he has only 40 dollars, and wants to buy only one hat for 13. 50. He wants to buy his friends braclets 3.25, but since you dont know how many friends its for, you will leave it as x.

There is only 40 dollars so you will use: ≤

The answer will be:

3.25x + 13.50 ≤ 40

Hope this helps.

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lys-0071 [83]

The expression for the total cost of their trip is 7 + 2x + 3y.

As per the question, assuming the number of bottles to be x and number of bags to be y. The equation will have one time fee of admission, product of cost of bottles and number of bottles and product of cost of bags and number of chips bags.

The one time fee and two products will be added to form the expression. Forming the equation now -

Expression = 7 + 2x + 3y

Therefore, the expression of trip when x bottles of water were bought during the visit is 7 + 2x + 3y.

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Use the Law of Sines to find the measure of angle J to the nearest degree.
rjkz [21]
\bf \textit{Law of sines}
\\ \quad \\
\cfrac{sin(\measuredangle A)}{a}=\cfrac{sin(\measuredangle B)}{b}=\cfrac{sin(\measuredangle C)}{c}\\\\
-----------------------------\\\\
\cfrac{sin(J)}{9.1}=\cfrac{sin(97^o)}{11}\implies sin(J)=\cfrac{9.1\cdot sin(97^o)}{11}
\\\\\\
\textit{now taking }sin^{-1}\textit{ to both sides}
\\\\\\
sin^{-1}\left[ sin(J) \right]=sin^{-1}\left( \cfrac{9.1\cdot sin(97^o)}{11} \right)
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Can someone help me with this question please?
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Step-by-step explanation:

ur gonna go 6 to the left and 5 up

7 0
2 years ago
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3(1-2x)=1/4(6x+9) what does x equal? <br> A) x=1/10<br> B) x=7/10<br> C) x=-12/7<br> D)x=-1/5
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Answer:

A

Step-by-step explanation:

3(1-2x)=1/4(6x+9)

3-6x=1 1/2x+2 1/4

-2 1/4          -2 1/4

3/4-6x=1 1/2x

    +6x  +6x

3/4=7 1/2x

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This trapezoid has been divided into two right triangles and a rectangle.
jok3333 [9.3K]

The area of the triangle on left is in²: 9

The area of the triangle on the right is in²: 9

The area of the rectangle is in²: 108

The area of the trapezoid is in²: 126

<h3>Area of Compound Shapes</h3>

This exercise requires your knowledge about the area of compound shapes. For solving this, you should:

  1. Identify the basic shapes;
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For finding the area, the steps are presented below.

  • STEP 1 - Identify the basic shapes.

       

       This trapezoid is composed of two triangles and one rectangle. Therefore, you should sum the area of these geometric figures.

  • STEP 2 - Find the area of the triangle.

        Area of the triangle - A_{triangle}=\frac{b*h}{2}. The figure shows:

        b= length of the base= 2in

        h=height=9 in

        Then,  A_{triangle}=\frac{b*h}{2}=\frac{2*9}{2} =\frac{18}{2}=9 in^2

Note that the triangles are equals, consequently, they present the same values for the area.

  • STEP 3 - Find the area of the rectangle.

       Area of the rectangle- A_{rectangle}={b*h}. The figure shows:

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        Then,  A_{rectangle}={b*h}=12*9=108 in^2 .

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