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3 years ago

Please help mee with the question

Mathematics

1 answer:

brilliants [131]3 years ago

6 0

Answer:

5x-8y

Step-by-step explanation:

4x-9y+x+y

=4x+-9y+x+y

=(4x+x)+(-9y+y)

=5x+-8y

=5x-8y

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Write each expression as an algebraic (nontrigonometric) expression in u, u > 0.

max2010maxim [7]

Answer:

$\displaystyle \sin\left(2\sec^{-1}\left(\frac{u}{10}\right)\right)=\frac{20\sqrt{u^2-100}}{u^2}\text{ where } u>0$

Step-by-step explanation:

We want to write the trignometric expression:

$\displaystyle \sin\left(2\sec^{-1}\left(\frac{u}{10}\right)\right)\text{ where } u>0$

As an algebraic equation.

First, we can focus on the inner expression. Let θ equal the expression:

$\displaystyle \theta=\sec^{-1}\left(\frac{u}{10}\right)$

Take the secant of both sides:

$\displaystyle \sec(\theta)=\frac{u}{10}$

Since secant is the ratio of the hypotenuse side to the adjacent side, this means that the opposite side is:

$\displaystyle o=\sqrt{u^2-10^2}=\sqrt{u^2-100}$

By substitutition:

$\displaystyle= \sin(2\theta)$

Using an double-angle identity:

$=2\sin(\theta)\cos(\theta)$

We know that the opposite side is √(u² -100), the adjacent side is 10, and the hypotenuse is u. Therefore:

$\displaystyle =2\left(\frac{\sqrt{u^2-100}}{u}\right)\left(\frac{10}{u}\right)$

Simplify. Therefore:

$\displaystyle \sin\left(2\sec^{-1}\left(\frac{u}{10}\right)\right)=\frac{20\sqrt{u^2-100}}{u^2}\text{ where } u>0$

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3 years ago

A right circular cylinder has a radius of 5 inches and a height of 10 inches. what is its volume?

Aloiza [94]

V=πr2h

v=π(5)^2(10)

v=250π

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3 years ago

A certain fish grows so that after t years of life its length is given by L(t) = 9 − 1/5t inches. Calculate the average rate of

vfiekz [6]

Answer:

Step-by-step explanation:

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L(t) = 9 − 1/5t

The average rate of growth is expressed as;

dL/dt = -1/5 (differential of a constant is zero)

Hence the average rate of growth over the first year of life is -1/5 in/year

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3 years ago

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Maru [420]

Answer:

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Step-by-step explanation:

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3 years ago

Read 2 more answers

Expression for the quotient of b divided by the difference of two minus 3

uysha [10]

Answer:

The required expression is

$\frac{b}{2 - 3} = - b$

Step-by-step explanation:

Difference of two minus three = 2-3

Quotient of b divided by the difference of two minus three is

$\frac{b}{2-3} = \frac{b}{-1} = - b$

Therefore, the required expression is

$\frac{b}{2-3} \ \ \ \ \ \ \ \ or \ \ \ \ \ \ \ \ - b$

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3 years ago