Answer:
No... provided no other information or no graph is provided.
Step-by-step explanation:
You can find the x-coordinate of the vertex which can be calculated using the two given x-intercepts. Using the symmetry of the parabola, it would just mean the vertex should lay midway between the x's. So the x-coordinate of the vertex is (12+35)/2=47/2.
However, we do not have enough information about the relationship between x and y to find the y-coordinate of the vertex.
All we are given is y=a(x-12)(x-35) (where a is real number) since we know the relationship is quadratic, and the zeros are 12 & 35.
So we could have many possible y-coordinates for our vertex since we don't know the value of a in our equation and we can plug in our x-coordinate for our vertex to find them all.
y=a(47/2-12)(47/2-35)
I'm just going to put everything to right of a in calculator:
y=-529/4 ×a
So that's all the possible y-coordinates for the vertex.
It's not 6 its literally just above 6 its ( 6.25 )
Answer:
Step-by-step explanation:
(x+5)² = x² + 10x + 25
Here's link to the answer:
tinyurl.com/wpazsebu
