#1: 4*5 + 4*6=20+24=44
#2: 4*(5+6)=4*11=44
Answer:
The equation does not have a real root in the interval ![\rm [0,1]](https://tex.z-dn.net/?f=%5Crm%20%5B0%2C1%5D)
Step-by-step explanation:
We can make use of the intermediate value theorem.
The theorem states that if
is a continuous function whose domain is the interval [a, b], then it takes on any value between f(a) and f(b) at some point within the interval. There are two corollaries:
- If a continuous function has values of opposite sign inside an interval, then it has a root in that interval. This is also known as Bolzano's theorem.
- The image of a continuous function over an interval is itself an interval.
Of course, in our case, we will make use of the first one.
First, we need to proof that our function is continues in
, which it is since every polynomial is a continuous function on the entire line of real numbers. Then, we can apply the first corollary to the interval
, which means to evaluate the equation in 0 and 1:

Since both values have the same sign, positive in this case, we can say that by virtue of the first corollary of the intermediate value theorem the equation does not have a real root in the interval
. I attached a plot of the equation in the interval
where you can clearly observe how the graph does not cross the x-axis in the interval.
The answer would be 60 to 30% i hope this helps<33
The problem presented with the word used as "divied" is very tricky and misleading to the point that it might create an understanding.
So we will approach this is in two ways.
If this was meant to be "divided by" then it would look like this:
6 / 192
If this was meant to be "divided to" then it would look like this:
192 / 6
Let us first solve for the first possible problem:
6 / 192 = ?
0.0312
0.0312 would be the answer.
Let us then solve for the second possible problem:
192 / 6 = ?
32 = ?
32 would be the answer.
So 0.0312 and 32 would be two possible answers to this problem.