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3 years ago

Please use ( y = mx +b )

Mathematics

1 answer:

Sindrei [870]3 years ago

6 0

Answer:

y= 2/5-1

Step-by-step explanation:

You get the 2/5 because you go 2 to the right and go 5 up, the -1 is because the x-int is at -1.

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PLEASE HELP MEEEEE!!!!!!!

OverLord2011 [107]

Answer:

Cheese: $4\frac{3}{8}$
Milk: $1\frac{2}{3}$
Pasta: $6\frac{1}{4}$

Step-by-step explanation:

Cheese:

$1\frac{3}{4} = \frac{7}{4}$
Set up a proportion: $\frac{\frac{7}{4} }{4} = \frac{x}{10}$
Cross multiply, then divide: 10 × 7/4 = 17.5, 17.5 ÷ 4 = 4.375
$4.375 = 4\frac{3}{8}$

Milk:

Set up a proportion: $\frac{\frac{2}{3} }{4} = \frac{x}{10}$
Cross multiply, then divide: 10 × 2/3 = $6\frac{2}{3}$ , $6\frac{2}{3}$ ÷ 4 = $1\frac{2}{3}$

Pasta:

$2\frac{1}{2} = \frac{5}{2}$
Set up a proportion: $\frac{\frac{5}{2} }{4} = \frac{x}{10}$
Cross multiply, then divide: 10 × 5/2 = 25, 25 ÷ 4 = 6.25
$6.25 = 6\frac{1}{4}$

I hope this helps!

4 0

3 years ago

Given the matrices: 1 2 A= 1 -1 2 1 1 B= 3 4 Calculate AB: C11 C12 [2.1] х 1 2 3 4 C21 C22 C11 = C12 = -2 C22 - C215 DONE

eduard

Answer:

$\:c_{11}=-2,\:\:\:c_{12}=-2$

$\:c_{21}=5,\:\:\:c_{22}=8$

Step-by-step explanation:

Given the matrices

$A=\begin{pmatrix}1&-1\\ 2&1\end{pmatrix}$

$B=\begin{pmatrix}1&2\\ \:3&4\end{pmatrix}$

Calculating AB:

$\begin{pmatrix}1&-1\\ \:\:2&1\end{pmatrix}\times \:\begin{pmatrix}1&2\\ \:\:3&4\end{pmatrix}=\begin{pmatrix}c_{11}&c_{12}\\ \:\:\:c_{21}&c_{22}\end{pmatrix}$

Multiply the rows of the first matrix by the columns of the second matrix

$=\begin{pmatrix}1\cdot \:1+\left(-1\right)\cdot \:3&1\cdot \:2+\left(-1\right)\cdot \:4\\ 2\cdot \:1+1\cdot \:3&2\cdot \:2+1\cdot \:4\end{pmatrix}$

$=\begin{pmatrix}-2&-2\\ 5&8\end{pmatrix}$

Hence,

$\begin{pmatrix}c_{11}&c_{12}\\ \:\:\:c_{21}&c_{22}\end{pmatrix}=\begin{pmatrix}-2&-2\\ \:5&8\end{pmatrix}$

Therefore,

$\:c_{11}=-2,\:\:\:c_{12}=-2$

$\:c_{21}=5,\:\:\:c_{22}=8$

5 0

3 years ago

Read 2 more answers

Litter such as leaves falls to the forest floor, where the action of insects and bacteria initiates the decay process. Let A be

Travka [436]

Answer:

D = L/k

Step-by-step explanation:

Since A represents the amount of litter present in grams per square meter as a function of time in years, the net rate of litter present is

dA/dt = in flow - out flow

Since litter falls at a constant rate of L grams per square meter per year, in flow = L

Since litter decays at a constant proportional rate of k per year, the total amount of litter decay per square meter per year is A × k = Ak = out flow

So,

dA/dt = in flow - out flow

dA/dt = L - Ak

Separating the variables, we have

dA/(L - Ak) = dt

Integrating, we have

∫-kdA/-k(L - Ak) = ∫dt

1/k∫-kdA/(L - Ak) = ∫dt

1/k㏑(L - Ak) = t + C

㏑(L - Ak) = kt + kC

㏑(L - Ak) = kt + C' (C' = kC)

taking exponents of both sides, we have

$L - Ak = e^{kt + C'} \\L - Ak = e^{kt}e^{C'}\\L - Ak = C"e^{kt} (C" = e^{C'} )\\Ak = L - C"e^{kt}\\A = \frac{L}{k} - \frac{C"}{k} e^{kt}$

When t = 0, A(0) = 0 (since the forest floor is initially clear)

$A = \frac{L}{k} - \frac{C"}{k} e^{kt}\\0 = \frac{L}{k} - \frac{C"}{k} e^{k0}\\0 = \frac{L}{k} - \frac{C"}{k} e^{0}\\\frac{L}{k} = \frac{C"}{k} \\C" = L$

$A = \frac{L}{k} - \frac{L}{k} e^{kt}$

So, D = R - A =

$D = \frac{L}{k} - \frac{L}{k} - \frac{L}{k} e^{kt}\\D = \frac{L}{k} e^{kt}$

when t = 0(at initial time), the initial value of D =

$D = \frac{L}{k} e^{kt}\\D = \frac{L}{k} e^{k0}\\D = \frac{L}{k} e^{0}\\D = \frac{L}{k}$

4 0

3 years ago

I Need Help Fast Please

lbvjy [14]

C. 130,90,130.

#01234, the tenths number stays the same
#56789, the tenths number go up 1 number

4 0

3 years ago

What is the quotient?<br><br><br><br> 8745/53 (8745/53 is a fraction)

iris [78.8K]

If this were to be put in this form: $53\sqrt{8745}$ the quotient we be on top, or another word the answer. I can't show it on here, but the answer is 165

6 0

3 years ago

Read 2 more answers