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riadik2000 [5.3K]
3 years ago
12

-17+6+(-3) simplify each expression show your work

Mathematics
1 answer:
Maru [420]3 years ago
4 0

THE ANSWER IS -14

-17+6+(-3)

-17+3

-14

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In △ACD, if AC ≅ AD, m∠A = (3x – 4)°, m∠C = (5x + 1)°, and m∠D = (7x – 27)°, find x and the measure of each angle. *
Tems11 [23]

Answer:

x = 14

A = 38

B = 71

C = 71

Step-by-step explanation:

Since we have a triangle, the addition of the measure of all the measure of the angles give 180

Thus;

3x-4 + 5x + 1 + 7x-27 = 180

15x-30 = 180

15x = 180 + 30

15x = 210

x = 210/15

x = 14

To get the measure of each of the angles, we substitute for x

A = 3x-4 = 3(14) - 4 = 38

B = 5x + 1 = 5(14) + 1 = 70 + 1 = 71

C = 7x - 27 = 7(14) - 27 = 98-27 = 71

5 0
3 years ago
If -2 and 3 are zeroes of quadratic polynomial xsquare + (a+1)x+b then find the value of and b
ohaa [14]

Answer:

a = - 2, b = - 6

Step-by-step explanation:

Substitute the values of the zeros into the polynomial and equate to zero.

x² +(a + 1)x + b

x = - 2 → (- 2)² - 2(a + 1) + b = 0 , that is

4 - 2a - 2 + b = 0

2 - 2a + b = 0 ( subtract 2 from both sides )

- 2a + b = - 2 → (1)

x = 3 → 3² + 3(a + 1) + b = 0, that is

9 + 3a + 3 + b = 0

12 + 3a + b = 0 ( subtract 12 from both sides )

3a + b = - 12 → (2)

Subtract (1) from (2) term by term to eliminate b

5a = - 10 ( divide both sides by 5 )

a = - 2

Substitute a = - 2 into either of the 2 equations and evaluate for b

Substituting into (2)

3(- 2) + b = - 12

- 6 + b = - 12 ( add 6 to both sides )

b = - 6

Thus a = - 2 and b = - 6

4 0
3 years ago
Find the sum of 46 + 42 + 38 + ... + (-446) + (-450)46+42+38+...+(−446)+(−450)
JulijaS [17]

sum of sequence Find the sum of 46 + 42 + 38 + ... + (-446) + (-450) is -25,250

<u>Step-by-step explanation:</u>

We need to find sum of sequence  : 46 + 42 + 38 + ... + (-446) + (-450)

Given sequence is an AP with following parameters as :

a=46\\d=42-46=-4

So , Let's calculate how many terms are there as :

⇒ a_n=a +(n-1)d

⇒ -450=46 +(n-1)(-4)

⇒ -496=(n-1)(-4)

⇒ \frac{-496}{-4}=n-1

⇒ 124=n-1

⇒ n=125

Sum of an AP is :

⇒ S_n = \frac{n}{2}(2a+(n-1)d)

⇒ S_1_2_5 = \frac{125}{2}(2(46)+(125-1)(-4))

⇒ S_1_2_5 = \frac{125}{2}(-404)

⇒ S_1_2_5 =-25,250

Therefore , sum of sequence Find the sum of 46 + 42 + 38 + ... + (-446) + (-450) is -25,250

3 0
3 years ago
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mafiozo [28]

Answer:

d?

Step-by-step explanation:

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3 years ago
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Ratling [72]
I think that the answer is 28
5 0
3 years ago
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