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riadik2000 [5.3K]
3 years ago
12

-17+6+(-3) simplify each expression show your work

Mathematics
1 answer:
Maru [420]3 years ago
4 0

THE ANSWER IS -14

-17+6+(-3)

-17+3

-14

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A food company sells salmon to various customers. The mean weight of the salmon is 37 lb with a standard deviation of 2 lbs. The
brilliants [131]

Answer:

The standard deviation for the mean weigth of Salmon is 2/3 lbs for restaurants, 2/7 lbs for grocery stores and 1/4 lbs for discount order stores.

Step-by-step explanation:

The mean sample of the sum of n random variables is

\overline{X} = \frac{X_1+X_2+...+X_n}{n}

If X_1, ..., X_n are indentically distributed and independent, like in the situation of the problem, then the variance of X_1 + .... + X_n will be the sum of the variances, in other words, it will be n times the variance of X_1 .

However if we multiply this mean by 1/n (in other words, divide by n), then we have to divide the variance by 1/n², thus \overkine{X} = \frac{V(X_1)}{n} and as a result, the standard deviation of \overline{X} is the standard deviation of X_1 divided by \sqrt{n} .

Since the standard deviation of the weigth of a Salmon is 2 lbs, then the standard deviations for the mean weigth will be:

  • Restaurants: We have boxes with 9 salmon each, so it will be \frac{2}{\sqrt{9}} = \frac{2}{3}
  • Grocery stores: Each carton has 49 salmon, thus the standard deviation is \frac{2}{\sqrt{49}} = \frac{2}{7}
  • Discount outlet stores: Each pallet has 64 salmon, as a result, the standard deviation is \frac{2}{\sqrt{64}} = \frac{1}{4}

We conclude that de standard deivation of the mean weigth of salmon of the types of shipment given is: 2/3 lbs for restaurants, 2/7 lbs for grocery stores and 1/4 lbs for discount outlet stores.

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3 years ago
Helpppp pls easy points
solmaris [256]

Answer:

153.94 is the area

Step-by-step explanation:

If the radius is 7p sqrt of 7p and you have your answer

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Please show all work and not just the answers.
Nuetrik [128]

I hope this helps you

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The right skewed data set means the data mostly lies in the right tail. There is majority of data present in the right tail of the data set. The mean, median and mod all are different for the rightly skewed data set.

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Can anyone please help me? Please please, i need help.
Papessa [141]

Answer:


Step-by-step explanation:


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