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atroni [7]
3 years ago
13

Vanessa typically works 8 hours per day in a normal 5 day work week. last week, however, vanessa had to take 90 minutes off on t

uesday, 45 minutes off on thursday, and she left two and a half hours early on friday. how many hours did vanessa work last week?
Mathematics
1 answer:
Rasek [7]3 years ago
4 0

The total number of hours Vanessa work in a week is:

total work hours = (8 hours / day) * 5 day / week

total work hours = 40 hours per week

The total number of hours she did not work:

<span>total hours did not work = (90 minutes)(1 hour / 60 minutes) + (45 minutes)(1 hour / 60 minutes)  + 2.5 hours</span>

total hours did not work = 4.75 hours

The amount of hours Vanessa work last week can be calculated using the formula:

work hours = total work hours - total hours did not work

work hours = 40 hours – 4.75 hours

<span>work hours = 35.25 hours</span>

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Step-by-step explanation:

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<u>Include exponent:</u>

f(0) =  - 9(1)

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3 years ago
Solve by completing the square<br><br> x^2-6x-16=0
Greeley [361]

Answer:

x = 8 or

x = -2

Step-by-step explanation:

<h2><em>Completing The Square</em><em>:</em></h2>

x² - 6x - 16 = 0

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a = 1

b = -6

c = -16

Now,

x² - 6x + [6/2(1)]² - [6/2(1)]² - 16 = 0

x² - 6x + (6/2)² - (6/2)² - 16 = 0

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(x - 3)² - 25 = 0

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x - 3 = +-√25

x - 3 = +- 5

x = 3 +- 5

x = 3 + 5 or x = 3 - 5

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7 0
3 years ago
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A wooden plank is leaning against a wall. The bottom of the plank is 3 feet from the wall. Answer each of the following question
Nadusha1986 [10]

AB = ==> distance between the bottom of the plank; and the wall ===> 3 ft.

C ====> 49 degrees

For letter a, to solve for AC:

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use sine :

sin A ===> opposite/hypotenuse

Solve:

sin 49 ====> 3/AC

AC ====> 3 / sin 49

AC ====> 3.96 ft.

For letter b, to solve for BC:

We are now given with the base (3 ft.); and; the hypotenuse (3.96 ft.) so we can use the Pythagorean theorem:

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Let:

a ===> AB

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(BC)^2 ===> 6.6816

sqrt (BC)^2 ===> sqrt 6.6816

Answer: BC ===> 2.58 ft.

Hope that helps!!!! : )

3 0
3 years ago
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