When it comes to freshwater wetlands, hydrology plays a large role in
nutrient stoichiometry and sensitivity to nutrient inputs. Although
wetland biogeochemists intuitively understand these important
relationships between landscape position, hydrology, and sensitivity to
nutrient inputs, these relationships have never been quantified using
geospatial data. The objective of this project will be to evaluate and
quantify the linkages between watershed catchment characteristics and
freshwater wetland nutrient sensitivity ur welcome
Polar bears are listed in red as they are belong to Endangered Species. These species are gonna extincting due to gradual changes by environmental factors.
Answer:
a) 99.93%
b) 99.98%
Explanation:
Given that:
Total population size was only around 18 individuals ( for black-footed ferret)
If the annual survival rate in the wild was 0.4%.
a)
What is the probability that all 18 would have died in a single year?
To find that; we multiply the annual survival rate in the wild with the total population; which is:
(0.4%×18) = 0.072%
Then; we subtract it from a total of 100% in order to determine the probability that all 18 would have died in a single year.
= (100.00% - 0.072%)
= 99.93%
b)
What is the probability that all 18 would have died in a single year if canine distemper was present?
Given that;
Because of the presence of canine distemper disease, the annual mortality rate might have been as high as 0.89.
To determine the probability; we have:
1 - Annual mortality rate = annual survival rate
1 - 0.89 = 0.11 %
Therefore, 0.11% of 18 individuals = (0.0011 × 18)
= 0.0198%
Probability that all 18 would have died in a single year if canine distemper was present = 100 - probability of annual survival rate
= (100 - 0.0198)%
= 99.98%
Answer:
include roots, stems, shoot buds, and leaves; they are not directly involved in sexual reproduction.
Answer:
0.27m
Explanation:
To get the energy
Potential energy= Mgh
M is Mass
G is acceleration due to gravity
H is height..
M= 0.29kg, h= ?
P=0.759. g=9.8m/s
Therefore,
0.759=0.29×9.8×h
H= 0.759÷2.842
H= 0.27m
