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4 years ago

PLEASE HELP! SEE ATTACHMENT! GEOMETRY!

Mathematics

2 answers:

geniusboy [140]4 years ago

8 0

Answer:

I think you have it right. the quantity in column a is greater

k0ka [10]4 years ago

3 0

The answer is B. Hope this helps!

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A bank is offering 3.5% simple interest on a savings account. If you deposit

arsen [322]

Answer: $525

Step-by-step explanation:

The formula for Simple interest is calculated as PRT where

P = Principal = $7500

R = Rate = 3.5%

T = Time = 2 years

Interest = PRT

= 7500 × 3.5% × 2

= 7500 × 0.035 × 2

= $525

5 0

3 years ago

Identify the equation that does not belong with the other three. Explain your reasoning. 5x = 20, 4b = 7, 8w = 32, 12y = 48

liubo4ka [24]

Answer:

4b = 7

Step-by-step explanation:

5x = 20 has solution x = 4

8w = 32 has solution w = 4

12y = 48 has solution y = 4

whereas 4b = 7 has solution b = $\frac{7}{4}$

The other 3 equations have a solution of 4 making 4b = 7 the odd one out

7 0

3 years ago

Find the absolute maximum and absolute minimum values of f on the given interval. f(t) = 2 cos(t) + sin(2t),[0, π/2].

castortr0y [4]

Answer:

The absolute maximum is $\frac{3\sqrt 3}2$ and the absolute minimum value is $0.$

Step-by-step explanation:

Differentiate of $f$ both sides w.r.t. $t$ ,

$f(t)=2 \cos t+\sin 2t$

$\Rightarrow f'(t)=-2\sin t+2\cos 2t$

Now take $f'(t)=0$

$\Rightarrow -2\sin t+2\cos 2t=0$

$\Rightarrow 2\cos 2t=2\sin t$

$\Rightarrow \cos 2t=\sin t$

$\Rightarrow 1-2\sin ^2t =\sin t \quad \quad [\because \cos 2t = 1-2\sin ^2t]$

$\Rightarrow 2\sin ^2t+\sin t-1=0$

$\Rightarrow 2\sin ^2t+2\sin t-\sin t-1=0$

$\Rightarrow 2\sin t(\sin t+1)-1(\sin t+1)=0$

$\Rightarrow (\sin t+1)(2\sin t-1)=0$

$\Rightarrow \sin t+1=0 \;\text{and}\; 2\sin t-1=0$

$\Rightarrow \sin t =-1 \;\text{and}\; \sin t =\frac 12$

In the interval $0\leq t\leq \frac {\pi}2$ , the answer to this problem is $\frac {\pi}6$

Now find the second derivative of $f(t)$ w.r.t. $t$ ,

$f''(t)=-2\cos t-4\sin 2t$

$\Rightarrow \left[f''(t)\right]_{t=\frac {\pi}6}=-2\times \frac {\sqrt 3}2-4\times \frac{\sqrt 3}2=-3\sqrt 3$

Thus, $f(t)$ is maximum at $t=\frac {\pi}6$ and minimum at $t=0$

$\left[f(t)\right]_{t=\frac {\pi}6}=2\times \frac {\sqrt 3}2+\frac{\sqrt 3}2=\frac{3\sqrt 3}2\;\text{and}\;\left[f(t)\right]_{t=\frac{\pi}2}= 2\times 0+0=0$

Hence, the absolute maximum is $\frac{3\sqrt 3}2$ and the absolute minimum value is $0$ .

7 0

3 years ago

Find the value of x.<br> 44 °<br> Х<br> x = [? ]°

Svetach [21]

Answer:

x = 136°

Step-by-step explanation:

The opposite angles of a cyclic quadrilateral are supplementary, that is

x + 44° = 180° (subtract 44° from both sides )

x = 136°

6 0

3 years ago

the figure at the right shows the dimensions of the garden in Marissa's back yard. What is the area of the garden?

vodka [1.7K]

The area of the garden is 74 square feet

<h3>How to determine the area of the garden?</h3>

The complete question is added as an attachment

From the attached figure, we have the following shapes and dimensions:

Rectangle: 10 by 5 feet
Trapezoid: Bases = 10 and 6; Height = 3

The rectangular area is

A1 = 10 * 5

Evaluate

A1 = 50

The area of the trapezoid is

A2 = 0.5 * Sum of parallel bases * height

This gives

A2 = 0.5 * (10 + 6) * 3

Evaluate

A2 = 24

The total area is

Total = A1 + A2

This gives

Total = 50 + 24

Evaluate

Total = 74

Hence, the area of the garden is 74 square feet