well, putting the movie in fifths, she watched 3/5, the whole movie will be 5/5 = 1.
![\begin{array}{ccll} \stackrel{movie}{fraction}&hour\\ \cline{1-2} \frac{3}{5}&\frac{5}{8}\\[1em] \underset{whole}{1}&x \end{array}\implies \cfrac{~~ \frac{3}{5}~~}{1}=\cfrac{~~ \frac{5}{8}~~}{x}\implies \cfrac{3}{5}x=\cfrac{5}{8}\implies \cfrac{3x}{5}=\cfrac{5}{8} \\\\\\ 24x=25\implies x = \cfrac{25}{24}\implies x = 1\frac{1}{24}\qquad \textit{1 hour, 2 minutes and 30 seconds}](https://tex.z-dn.net/?f=%5Cbegin%7Barray%7D%7Bccll%7D%20%5Cstackrel%7Bmovie%7D%7Bfraction%7D%26hour%5C%5C%20%5Ccline%7B1-2%7D%20%5Cfrac%7B3%7D%7B5%7D%26%5Cfrac%7B5%7D%7B8%7D%5C%5C%5B1em%5D%20%5Cunderset%7Bwhole%7D%7B1%7D%26x%20%5Cend%7Barray%7D%5Cimplies%20%5Ccfrac%7B~~%20%5Cfrac%7B3%7D%7B5%7D~~%7D%7B1%7D%3D%5Ccfrac%7B~~%20%5Cfrac%7B5%7D%7B8%7D~~%7D%7Bx%7D%5Cimplies%20%5Ccfrac%7B3%7D%7B5%7Dx%3D%5Ccfrac%7B5%7D%7B8%7D%5Cimplies%20%5Ccfrac%7B3x%7D%7B5%7D%3D%5Ccfrac%7B5%7D%7B8%7D%20%5C%5C%5C%5C%5C%5C%2024x%3D25%5Cimplies%20x%20%3D%20%5Ccfrac%7B25%7D%7B24%7D%5Cimplies%20x%20%3D%201%5Cfrac%7B1%7D%7B24%7D%5Cqquad%20%5Ctextit%7B1%20hour%2C%202%20minutes%20and%2030%20seconds%7D)
Answer:
43
Step-by-step explanation:
so when subtracting a negative number the number becomes positive and the problem become 28 + 15 because the negative (subtraction) signs cancel out
Answer:
Step-by-step explanation:
Let y be the total charge and x no of hours spent for cutting the lawn,
Then for Allan we have the equation as
y = 8.50x+15
SInce 15 is the fixed charge and 8.50 is charged per hour we get the above equation for Allan.
Next similarly for Taylor, we have fixed charges 12 and variale 9.25
y =9.25x+12
When Taylor total charges is greater than Allan's total charge
we have 9.25x+12>8.5x+15
Simplify to get
0.75x>3
Or x>4
Whenever x i.e. no of hours exceed 4, Taylor charges will be greater than that of Allan