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sp2606 [1]
3 years ago
7

When solving the equation 2/3 b 5 = 7, you should first ? from both sides. Then you should multiply both sides by the ? of ?. Yo

ur answer will be ? .
Mathematics
1 answer:
Tju [1.3M]3 years ago
3 0
Depends on the question...

If your question is 2/3b + 5 = 7, then follow this one
\frac{2}{3}b + 5 = 7\\\\\sf You~ first~subtract~ 5 ~on ~both~ sides\\\\Then ~you~multiply~by~\frac{3}{2}~on~both~sides.\\\\ So...\\\\ \frac{2}{3}b + 5 - 5 = 7 - 5\\\\\frac{2}{3}b = 2\\\\\frac{2}{3}b \times \frac{3}{2} = 2 \times \frac{3}{2}\\\\b = 3
Your final answer will be b = 3


If your question is 2/3b - 5 = 7, then follow this one
\frac{2}{3}b - 5 = 7\\\\\sf You~ first~add~ 5 ~on ~both~ sides\\\\Then ~you~multiply~by~\frac{3}{2}~on~both~sides.\\\\ So...\\\\ \frac{2}{3}b - 5 + 5 = 7+5 \\\\\frac{2}{3}b = 12\\\\\frac{2}{3}b \times \frac{3}{2} = 12 \times \frac{3}{2}\\\\b =18
Your final answer will be b = 18
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There are eight teams in a league. I’m how many ways can the teams finish first, second, and third?
jolli1 [7]

Answer:

There are 336 ways can the teams finish first, second, and third

Step-by-step explanation:

Total no. of teams = 8

First prize is given to one of the 8 teams

So, no. of teams left for second prize = 8-1 =7

Second prize is given to one of the remaining 7 teams

So, no. of teams left for third prize = 7-1=6

So,the teams finish first, second, and third in no. of ways =8 \times 7 \times 6

The teams finish first, second, and third in no. of ways = 336

Hence there are 336 ways can the teams finish first, second, and third

3 0
3 years ago
Please help me with this homework
mihalych1998 [28]
Both questions are true
5 0
3 years ago
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What is the sum of -14 and -8?
Amanda [17]
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3 0
3 years ago
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Please help: <br><br> 12x^4(-5/6x^3y^2)<br><br> If possible, include steps<br><br> Thanks.
tangare [24]
---------------------------------------------------------------------------------------
Question
---------------------------------------------------------------------------------------
12x^4(- \frac{5}{6} x^3y^2)

---------------------------------------------------------------------------------------
Multiply the constant: 12 x (-5/6)
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-10x^4( x^3y^2)

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Multiply the x (we add the power together when we multiply)
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-10x^7y^2

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Answer: -10x⁷y²
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4 0
3 years ago
Gwendolyn is asked to solve the equation -43 – 3) = 20. She sh
choli [55]

Answer:

-4x + 12 = 20 is incorrect. she added 12 to 20 instead of subtracting 12 from both sides.

Step-by-step explanation:

It should have been, write problem

-4(x - 3) = 20

Use distributive property.

-4x + 12 = 20

subtract 12 from each side

-4x =8

divide each side by -4

x = -2

4 0
3 years ago
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