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3 years ago

Please help and give a reasonable answer.

Mathematics

2 answers:

CaHeK987 [17]3 years ago

7 0

Answer:

Step-by-step explanation:

Lerok [7]3 years ago

6 0

Answer: the median and they should predict size 8

Step-by-step explanation:

It is this answer because if you put the numbers in order from least to greatest and then start to find the median you will get two answers for the median and the numbers you should get are two 8 so then you add the two 8's up and then you get 16 so then you divide it by 2 and you will get 8 and that is your answer.

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HELPP PLEASE DUE TOMMOROW PLEASE ANSWER QUESTION B

marin [14]

Answer:

28 non-blue marbles.

Step-by-step explanation:

Initial probability of choosing a blue marble = 4/12

Let the number of non-blue marbles to be added be x.

$\frac{4}{12+x} =\frac{1}{10}$

$12+x=40$ (cross multiply)

$x=28$

4 0

3 years ago

A teacher has a total of 7/9 bucket of water to pour into pots with flowers that are standing in equal quantities on two windows

AleksAgata [21]

Answer:

14 pots

Step-by-step explanation:

if teacher pours 1/18 in each pot and there was 7/9 buckets in total, 9 fits into 18 twice so just 7X2 =14 and 9X2=18 so 14 pots were watered

hope this helps

3 0

2 years ago

Find the differential coefficient of <br><img src="https://tex.z-dn.net/?f=e%5E%7B2x%7D%281%2BLnx%29" id="TexFormula1" title="e^

Gemiola [76]

Answer:

$\rm \displaystyle y' = 2 {e}^{2x} + \frac{1}{x} {e}^{2x} + 2 \ln(x) {e}^{2x}$

Step-by-step explanation:

we would like to figure out the differential coefficient of $e^{2x}(1+\ln(x))$

remember that,

the differential coefficient of a function y is what is now called its derivative y', therefore let,

$\displaystyle y = {e}^{2x} \cdot (1 + \ln(x) )$

to do so distribute:

$\displaystyle y = {e}^{2x} + \ln(x) \cdot {e}^{2x}$

take derivative in both sides which yields:

$\displaystyle y' = \frac{d}{dx} ( {e}^{2x} + \ln(x) \cdot {e}^{2x} )$

by sum derivation rule we acquire:

$\rm \displaystyle y' = \frac{d}{dx} {e}^{2x} + \frac{d}{dx} \ln(x) \cdot {e}^{2x}$

Part-A: differentiating $e^{2x}$

$\displaystyle \frac{d}{dx} {e}^{2x}$

the rule of composite function derivation is given by:

$\rm\displaystyle \frac{d}{dx} f(g(x)) = \frac{d}{dg} f(g(x)) \times \frac{d}{dx} g(x)$

so let g(x) [2x] be u and transform it:

$\displaystyle \frac{d}{du} {e}^{u} \cdot \frac{d}{dx} 2x$

differentiate:

$\displaystyle {e}^{u} \cdot 2$

substitute back:

$\displaystyle \boxed{2{e}^{2x} }$

Part-B: differentiating ln(x)•e^2x

Product rule of differentiating is given by:

$\displaystyle \frac{d}{dx} f(x) \cdot g(x) = f'(x)g(x) + f(x)g'(x)$

let

$f(x) \implies \ln(x)$
$g(x) \implies {e}^{2x}$

substitute

$\rm\displaystyle \frac{d}{dx} \ln(x) \cdot {e}^{2x} = \frac{d}{dx}( \ln(x) ) {e}^{2x} + \ln(x) \frac{d}{dx} {e}^{2x}$

differentiate:

$\rm\displaystyle \frac{d}{dx} \ln(x) \cdot {e}^{2x} = \boxed{\frac{1}{x} {e}^{2x} + 2\ln(x) {e}^{2x} }$

Final part:

substitute what we got:

$\rm \displaystyle y' = \boxed{2 {e}^{2x} + \frac{1}{x} {e}^{2x} + 2 \ln(x) {e}^{2x} }$

and we're done!

6 0

3 years ago

If the Federal Reserve sets the reserve rate to 2%, what is the resulting money

Yuliya22 [10]

Answer:A

Step-by-step explanation:

6 0

3 years ago

Can u solve this for me

Studentka2010 [4]

X^2 + 4x + 16 is the answer

8 0

3 years ago