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4 years ago

Find the range of y=3/2cos4x-1

Mathematics

1 answer:

MrRissso [65]4 years ago

5 0

Answer:

Range = [- 2.5, 0.5] = [ - 5/2, 1/2]

Step-by-step explanation:

Smallest value of cos α = - 1,

largest value of cos α = 1.

When cos 4x = - 1, y=3/2cos4x-1 = 3/2*(-1) - 1 = - 5/2 = - 2 1/2 = - 2.5

When cos 4x = 1, y=3/2cos4x-1 = 3/2*1 - 1 = 1/2 = 0.5

Range = [- 2.5, 0.5] = [ - 5/2, 1/2]

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Step-by-step explanation:

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4 years ago

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I need help finding the domain and range for the graph

Taya2010 [7]

Answer:

Step-by-step explanation:

take two points to find the equation:

(0,4),(-2,0)

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domain(-∞,∞) , range (-∞,∞)

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4 years ago

Find the solution of the square root of the quantity of x plus 2 plus 4 equals 8, and determine if it is an extraneous solution

Iteru [2.4K]

Consider the equation:

$\sqrt{x+2}+4 = 8$

Subtracting '4' from both the sides of the equation, we get as

$\sqrt{x+2}+4-4= 8-4$

$\sqrt{x+2}= 4$

Squaring on both the sides of the equation, we get

$(\sqrt{x+2})^2 = (4)^2$

$x+2 = 16$

Subtracting '2' from both the sides of the equation, we get

$x+2-2=16-2$

x=14

Since, An extraneous solution is a solution that arises from the solving process that is not really a solution at all. But, in this equation x=14 is the solution of the given equation.

Hence, it is not an extraneous solution.

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4 years ago

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The scale on a map is 1 :50000.

mestny [16]

Answer:

The actual area of the field in square kilometers is $30000000 km^2$

Step-by-step explanation:

Scale : 1 cm = 50000 km

Area of field on map = $1.2 cm^2$

Now , 1 cm = 5000 km

$1 cm^2 = (5000 km)^2$

We are supposed to find the actual area of the field in square kilometers.

So, the actual area of the field in sq. km = $1.2 \times (5000)^2$

Actual area of the field in sq. km $=30000000 km^2$

Hence the actual area of the field in square kilometers is $30000000 km^2$

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3 years ago

John ran 1 1/4 laps in 2 minutes. How many laps did John run on average per minutes?

alukav5142 [94]

Answer:

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