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leva [86]
3 years ago
10

PLS HELLP ILL GIVE YOU BRAINALIST

Mathematics
1 answer:
irina [24]3 years ago
4 0

Answer:

88 units

Step-by-step explanation:

The required perimeter is 88 units.

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What is the radius of the circle whose equation is x^2 + y^2 = 8
gogolik [260]
√8

for the equations of circles: x²+y²= (radius)²
5 0
3 years ago
a regular pentagon-based pyramid has 5 faces which are equilateral triangles the perimeter of it's net is 70cm what is the perim
netineya [11]

Answer:

35cm

Step-by-step explanation:

The net of a regular pentagon has 10 sides.

Since each of the faces are equilateral triangles, the side lengths are equal.

Therefore:

Length of each side of the net = 70/10 =7cm

Therefore, the base is a regular pentagon of side length 7cm.

The perimeter of the base of the pyramid = 5 X 7

=35cm

The perimeter of the base of the pyramid is 35cm.

3 0
3 years ago
The transformation T = [0 1 -1 0] is applied the figure below.
Margaret [11]

Answer:

<h2>a.) reflect across x-axis</h2>

Step-by-step explanation:

The transformation described is about multiplying the vertical value by -1:

(x,y) \implies (x,-y)

That means all vertical coordinates will change to the opposite side, but all horizontal coordinates will maintain at the same coordinate.

As a result, we'll have a reflection across the x-axis, because the y coordinates were transformed.

Therefore, the right answer is A.

4 0
3 years ago
A metal worker has several 1-kilogram bars of a metal alloy that contain 23% copper and several 1-kilogram bars that contain 79%
astraxan [27]

Answer:

30 each of 23% bars and 18 each of 79% bars

Step-by-step explanation:

If x is the number of 1 kg 23% copper bars, and y is the number of 1 kg 79% copper bars, then:

x + y = 48

0.23x + 0.79y = 0.44(48)

Substituting and solving:

0.23x + 0.79(48-x) = 0.44(48)

0.23x + 37.92 - 0.79x = 21.12

16.8 = 0.56x

x = 30

y = 48 - x

y = 18

You need 30 each of 23% bars and 18 each of 79% bars.

4 0
3 years ago
What inergers that are greater than zero
Sav [38]
Half of all the integers are ... all of the positive "counting numbers".

The total number is infinite, so I can't list them here.  But if you start at '1 '
and count, you can never name <em>ALL</em> of them, but you can name <em>as many</em>
of them as you want to.
7 0
3 years ago
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