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Alexeev081 [22]
3 years ago
14

Rachel has a box in the shape of a prism with a square base. The capacity of the box is 150 cubic inches. The height of the box

(y) is times the base length of the box (x). Find the approximate height and the length of the box.
A. x = 4 and y = 6
B. x = 5 and y = 7.5
C. x = 4.2 and y = 6.3
D. x = 4.6 and y = 6.9
Mathematics
1 answer:
Alex777 [14]3 years ago
8 0

Answer:

Step-by-step explanation:

What do we know about that prism?

It's a rectangular prism with a square base.

Height: y (from question)

base length: x (from question)

base width: x (from question, since it's a square base).

Total volume: 150 cu inches

The question lacks a relationship between x and y the "is __ times", but we can see from the answer choices that they all show a constant relationship:

y = 1.5 x  

The volume of a prism is obtained by  multiplying the lengths of its 3 dimensions: V = length * width * height.  In our case, we then have

150 = x * x *  y

then we replace y by its x-expressed equivalent:

150 = x * x * (1.5x) = 1.5x³

then we isolate x³ by dividing each side by 1.5

x³ = 100, we do the cubic root on each side

x = 4.64

So, answer is D. x = 4.6 and y = 6.9

If you you 4.64 * 4.64 * 6.96 = you get 149.8, which is very close to 150.

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If you're using the app, try seeing this answer through your browser:  brainly.com/question/2822772

_______________


Evaluate the indefinite integral:

\mathsf{\displaystyle\int\! \frac{cos\,x}{sin^2\,x}\,dx}\\\\\\&#10;=\mathsf{\displaystyle\int\! \frac{1}{(sin\,x)^2}\cdot cos\,x\,dx\qquad\quad(i)}


Make the following substitution:

\mathsf{sin\,x=u\quad\Rightarrow\quad cos\,x\,dx=du}


and then, the integral (i) becomes

=\mathsf{\displaystyle\int\! \frac{1}{u^2}\,du}\\\\\\&#10;=\mathsf{\displaystyle\int\! u^{-2}\,du}


Integrate it by applying the power rule:

\mathsf{=\dfrac{u^{-2+1}}{-2+1}+C}\\\\\\&#10;\mathsf{=\dfrac{u^{-1}}{-1}+C}\\\\\\&#10;\mathsf{=-\,\dfrac{1}{u}+C}


Now, substitute back for u = sin x, so the result is given in terms of x:

\mathsf{=-\,\dfrac{1}{sin\,x}+C}\\\\\\&#10;\mathsf{=-\,csc\,x+C}


\therefore~~\boxed{\begin{array}{c}\mathsf{\displaystyle\int\! \frac{cos\,x}{sin^2\,x}\,dx=-\,csc\,x+C} \end{array}}\qquad\quad\checkmark


I hope this helps. =)


Tags:  <em>indefinite integral substitution trigonometric trig function sine cosine cosecant sin cos csc differential integral calculus</em>

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Answer:

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Step-by-step explanation:

The factors are the set of tiles down the left side: x + 1 + 1 = (x +2), and the set of tiles across the top: x + x + 1 = (2x +1)

Your factored form is shown in choice D:

  (x +2)(2x +1)

_____

<em>Additional comment</em>

The point of this sort of diagram is to show you how the factors work together to give you the product. Each tile in the middle of the figure represents the product of the tile on the top line and the tile in the left column.

The product of x and x is x².

The product of 1 and x is x.

The product of 1 and 1 is 1.

The product of the two factors is the sum of all the tiles in the middle of the diagram: 2x² +5x +2.

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2 years ago
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