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2 years ago

5

A printer is printing photos. For every 8 photos, the printer takes 2 minutes. Complete the table below showing the number of ph

otos and the time it takes to print them.

1 answer:

GaryK [48]2 years ago

4 0

Min. Photos
2. 8
4. 16
8. 24
…. ….

I think this is what your asking. Hope this helps!

For every two minutes you +8 to the amount of photos you have. And if you only by one minute you +4 to the amount of photos you have.

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Given g(x) = −3x + 4

Goshia [24]

Answer:

The average rate of change of <em>g</em> from <em>x</em> = <em>a</em> to<em> x</em> = <em>a</em> + <em>h</em> is -3.

Step-by-step explanation:

We are given the function:

$g(x) = -3x + 4$

And we want to determine its average rate of change of the function for <em>x</em> = <em>a</em> and <em>x</em> = <em>a</em> + <em>h</em>.

To determine the average rate of change, we find the slope of the function between the two points. In other words:

$\displaystyle \text{Avg} = \frac{g(a + h) - g(a) }{(a + h ) - a}$

Simplify:

$\displaystyle \begin{aligned} \text{Avg} &= \frac{g(a + h) - g(a) }{(a + h ) - a} \\ \\ &=\frac{(-3(a+h) + 4) - (-3a+4)}{h} \\ \\ &= \frac{(-3a -3h + 4) + (3a - 4) }{h} \\ \\ &= \frac{-3h}{h} \\ \\ &= -3\end{aligned}$

In conclusion, the average rate of change of <em>g</em> from <em>x</em> = <em>a</em> to <em>x</em> = <em>a</em> + <em>h</em> is -3.

This is the expected result, as function <em>g</em> is linear, so its rate of change would be constant.

3 0

3 years ago

snow_tiger [21]

Answer:

Now, derive it from the calculations

Step-by-step explanation:

Net income = 100% = N120,000

therefore

1. Food

40%/100% = 2/5 of N120,000

= N48,000

2.Housing

30%/100% = 3/10 of N120,000

= N36,000

3. Savings

20%/100% = 2/10 (or 1/5) of N120,000

= N24,000

4. Miscellaneous

10%/100% = 1/10 of N120,000

= N 12,000

Quick mathmy friend

3 0

2 years ago

- what is the answer to 3t^2+11t-6

Wittaler [7]

I think the answer maybe 9t+5x

8 0

3 years ago

A rectangular field with one side along a river is to be fenced. Suppose that no fence is needed along the river, the fence on t

Andreas93 [3]

Answer:

a) Side Parallel to the river: 200 ft

b) Each of the other sides: 400 ft

Step-by-step explanation:

Let L represent side parallel to the river and W represent width of fence.

The required fencing (F) would be $F=L+2W$ .

We have been given that field must contain 80,000 square feet. This means area of field must be equal to 80,000.

$LW=80,000...(1)$

We are told that the fence on the side opposite the river costs $20 per foot, and the fence on the other sides costs $5 per foot, so total cost (C) of fencing would be $C=20L+5(2W)\Rightarrow 20L+10W$ .

From equation (1), we will get:

$L=\frac{80,000}{W}$

Upon substituting this value in cost equation, we will get:

$C=20(\frac{80,000}{W})+10W$

$C=\frac{1600,000}{W}+10W$

$C=1600,000W^{-1}+10W$

To minimize the cost, we need to find critical points of the the derivative of cost function as:

$C'=-1600,000W^{-2}+10$

$-1600,000W^{-2}+10=0$

$-1600,000W^{-2}=-10$

$-\frac{1600,000}{W^2}=-10$

$-10W^2=-1,600,000$

$W^2=160,000$

$\sqrt{W^2}=\pm\sqrt{160,000}$

$W=\pm 400$

Since width cannot be negative, therefore, the width of the fencing would be 400 feet.

Now, we will find the 2nd derivative as:

$C''=-2(-1600,000)W^{-3}$

$C''=3200,000W^{-3}$

$C''=\frac{3200,000}{W^3}$

Now, we will substitute $W=400$ in 2nd derivative as:

$C''(400)=\frac{3200,000}{400^3}=\frac{3200,000}{64000000}=0.05$

Since 2nd derivative is positive at $W=400$ , therefore, width of 400 ft of the fencing will minimize the cost.

Upon substituting $W=400$ in $L=\frac{80,000}{W}$ , we will get:

$L=\frac{80,000}{400}\\\\L=200$

Therefore, the side parallel to the river will be 200 feet.

4 0

3 years ago

Describe the relationship between two variables when the correlation coefficient r is one of the following.(a) near –1weak or no

AlexFokin [52]

Step-by-step explanation:

I don't know this math yet

sorry

7 0

3 years ago