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bija089 [108]
3 years ago
13

Given f(x) = 17-X^2what is the average rate of change in f(x) over the interval [1, 5]?

Mathematics
2 answers:
aliya0001 [1]3 years ago
8 0

Answer:

-6

Step-by-step explanation:

The formula for finding the rate of change is:

Rate\ of\ change=\frac{f(b)-f(a)}{b-a}

The interval is [1,5]

So, a = 1 and b=5

f(1) = 17 - (1)^2\\ =17-1\\=16\\f(5) = 17-(5)^2\\=17-25\\=-8

Putting in the values

Rate\ of\ change = \frac{f(5)-f(1)}{5-1} \\=\frac{-8-16}{5-1}\\= \frac{-24}{4}\\ =-6

The average rate of change is -6 ..

kykrilka [37]3 years ago
7 0

Answer:

-6

Step-by-step explanation:

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