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3 years ago

Given f(x) = 17-X^2what is the average rate of change in f(x) over the interval [1, 5]?

Mathematics

2 answers:

aliya0001 [1]3 years ago

8 0

Answer:

-6

Step-by-step explanation:

The formula for finding the rate of change is:

$Rate\ of\ change=\frac{f(b)-f(a)}{b-a}$

The interval is [1,5]

So, a = 1 and b=5

$f(1) = 17 - (1)^2\\ =17-1\\=16\\f(5) = 17-(5)^2\\=17-25\\=-8$

Putting in the values

$Rate\ of\ change = \frac{f(5)-f(1)}{5-1} \\=\frac{-8-16}{5-1}\\= \frac{-24}{4}\\ =-6$

The average rate of change is -6 ..

kykrilka [37]3 years ago

7 0

Answer:

-6

Step-by-step explanation:

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3 years ago

Show all work below to answer the following for a certain city that had a population of 150,000 in the year 2010. In 2020, the p

Gelneren [198K]

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For solving this question, you should apply the Population Growth Equation.

<h3>Population Growth Equation</h3>

The formula for the Population Growth Equation is:

$P_f=P_o*(1+\frac{R}{100} )^t$

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r=growth rate

t= time (years)

STEP 1 - Find the constant rate of continuous growth, k, for this population.

For this exercise, you have:

Pf= future population= 185,000 in 2020.

Po=initial population =150,000 in 2010.

r=growth rate= ?

t= time (years)=2020-2010=10

Then,

$P_f=P_o*(1+\frac{R}{100} )^t\\ \\ 185000=150000\cdot \left(1+\frac{R}{100}\:\right)^{10}\\ \\ \left(1+\frac{R}{100}\right)^{10}=\frac{185000}{150000} \\ \\ \left(1+\frac{R}{100}\right)^{10}=\frac{37}{30}\\ \\ R=100\sqrt[10]{\frac{37}{30}}-100=2.11935\%$

STEP 2 - Find the <em>t</em> for population 250,000 people.

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Read more about the population growth equation here:

brainly.com/question/25630111

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Step-by-step explanatioFeel pleasure to help u:

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