Question

Given f(x) = 17-X^2what is the average rate of change in f(x) over the interval [1, 5]?

Answer 1

Answer:

-6

Step-by-step explanation:

The formula for finding the rate of change is:

$Rate\ of\ change=\frac{f(b)-f(a)}{b-a}$

The interval is [1,5]

So, a = 1 and b=5

$f(1) = 17 - (1)^2\\ =17-1\\=16\\f(5) = 17-(5)^2\\=17-25\\=-8$

Putting in the values

$Rate\ of\ change = \frac{f(5)-f(1)}{5-1} \\=\frac{-8-16}{5-1}\\= \frac{-24}{4}\\ =-6$

The average rate of change is -6 ..

Answer 2

Answer:

-6

Step-by-step explanation: