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iren2701 [21]
4 years ago
14

The average of 8 numbers is 10. the average of 6 of the numbers is 12 what is the average of the other 2 numbers

Mathematics
1 answer:
omeli [17]4 years ago
7 0
So, all 8 numbers added up would equal 80. and all 6 numbers added up would equal 72. The subtract them. 80-72 is 8. Then divide by 2 because there are 2 numbers. 8/2 is 4. (4 is your answer)
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Find the zeros of x3 +2X^2-23x-60
laila [671]
Hello,

P(x)=x^3+2x²-23x-60
P(-4)=(-4)^3+2*(-4)²-23*(-4)-60=0
P(-3)=(-3)^4+2*(-3)²-23*(-3)-60=0
P(5)=5^3+2*5²-23*5-60=0
Zeros are -4,-3,5


5 0
3 years ago
Solve<br>(10) x 2 - (-7)^2​
erik [133]

Answer:

-39

Step-by-step explanation:

20-49

=49-20 but negative

=-39

5 0
4 years ago
Read 2 more answers
Round 7.788 to the nearest hundredth.
nevsk [136]

Answer:

7.79

Step-by-step explanation:

A hundredth is the second number after the decimal. For example, in the number 100.234, the "3" would be the hundredth, the "2" would be the tenth, and the "4" would be the thousandth.

To round to the nearest hundredth, you have to look at the thousandth because when rounding, you look at the next number to decide whether to round up or down.

Since 8 is in the thousandth place in this question, and 8 is bigger than 5, you round up. So, you round the "8" in the hundredths place up to 9.

Therefore, you get 7.79.

6 0
3 years ago
. The time taken by a randomly selected applicant for a mortgage to fill out a certain form has a normal probability distributio
ki77a [65]

Answer:

Probability that the sample average time taken is less than 11 minutes for Day 1 is 0.86864.

Probability that the sample average time taken is less than 11 minutes for Day 2 is 0.88877.

Step-by-step explanation:

We are given that the time taken by a randomly selected applicant for a mortgage to fill out a certain form has a normal probability distribution with average time 10 minutes and a standard deviation of 2 minutes.

Also, five individuals fill out the form on Day 1 and six individuals fill out the form on Day 2.

(a) Let \bar X = <u>sample average time taken</u>

The z score probability distribution for sample mean is given by;

                                Z  =  \frac{\bar X-\mu}{\frac{\sigma}{\sqrt{n} } } ~ N(0,1)

where, \mu = population mean time = 10 minutes

            \sigma = standard deviation = 2 minutes

            n = sample of individuals fill out form on Day 1 = 5

Now, the probability that the sample average time taken is less than 11 minutes for Day 1 is given by = P(\bar X < 11 minutes)

         P(\bar X < 11 minutes) = P( \frac{\bar X-\mu}{\frac{\sigma}{\sqrt{n} } } < \frac{11-10}{\frac{2}{\sqrt{5} } } ) = P(Z < 1.12) = <u>0.86864</u>

<em />

<em>The above probability is calculated by looking at the value of x = 1.12 in the z table which has an area of 0.86864.</em>

(b) Let \bar X = <u>sample average time taken</u>

The z score probability distribution for sample mean is given by;

                                Z  =  \frac{\bar X-\mu}{\frac{\sigma}{\sqrt{n} } } ~ N(0,1)

where, \mu = population mean time = 10 minutes

            \sigma = standard deviation = 2 minutes

            n = sample of individuals fill out form on Day 2 = 6

Now, the probability that the sample average time taken is less than 11 minutes for Day 2 is given by = P(\bar X < 11 minutes)

         P(\bar X < 11 minutes) = P( \frac{\bar X-\mu}{\frac{\sigma}{\sqrt{n} } } < \frac{11-10}{\frac{2}{\sqrt{6} } } ) = P(Z < 1.22) = <u>0.88877</u>

<em>The above probability is calculated by looking at the value of x = 1.22 in the z table which has an area of 0.88877.</em>

5 0
4 years ago
Suppose you know that ∠S and ∠Y are complementary, and that m∠S = 2(m∠Y) − 90°. Find m∠Y.
exis [7]

Answer:

Y=60

Step-by-step explanation:

S+Y=90

S=(2*Y)-90

Y+2Y-90=90

3Y=180

Y=60

Plug back into S+Y=90

S+60=90

S=30

4 0
3 years ago
Read 2 more answers
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