Answer:
0.9936 is the probability that the student will fail.
Step-by-step explanation:
We are given the following information:
We treat adult guessing correct answer as a success.
P(guess correct answer) = 0.2
Then the number of correct guesses follows a binomial distribution, where
where n is the total number of observations, x is the number of success, p is the probability of success.
Now, we are given n = 10
The student needs atleast 6 correct answer to pass the test. We have to calculate the probability that the student will fail.
We have to evaluate:
0.9936 is the probability that the student will fail.
The given expression is a (A) linear expression.
<h3>
What are linear expressions?</h3>
- A linear expression is an algebraic expression in which each term is a constant or a variable raised to the first power.
- To put it another way, none of the exponents may be greater than 1. x2 is a variable raised to the second power, whereas x is a variable raised to the first power.
- A constant is represented by the number 5.
- Reduce the equation as much as feasible to the form y = mx + b. Examine your equation for exponents.
- It is nonlinear if it has exponents. Your equation is linear if it contains no exponents.
- 2x - 3 = 0, 2y = 8, m + 1 = 0, x/2 = 3, x + y = 2, 3x - y + z = 3 are some instances of linear equations.
Therefore, the given expression is a (A) linear expression.
Know more about linear expressions here:
brainly.com/question/14323743
#SPJ4
The correct question is given below:
Classify the expression: 5x 2.
(A) linear expression
(B) quadratic expression
(C) cubic expression
(D0 quartic expression
Answer:
18
Step-by-step explanation:
Hope this helps!
Answer:
![\frac{9}{17}](https://tex.z-dn.net/?f=%5Cfrac%7B9%7D%7B17%7D)
Step-by-step explanation:
Given that a hat contains n coins, f of which are fair, and b of which are biased to land heads with probability 2/3
A coin is drawn from the hat and tossed twice. The first time it lands heads, and the second time it lands tails.
There are two possibilities. Either fair coin is drawn or biased is drawn.
Let A1 = I coin drawn and A2 = II coin is drawn.
![P(A1)=P(A2) = 0.5](https://tex.z-dn.net/?f=P%28A1%29%3DP%28A2%29%20%3D%200.5)
B= the first toss lands head and II tails.
![P(A1\bigcap B) = \frac{1}{2} [\frac{1}{2} ]^2\\= \frac{1}{8}](https://tex.z-dn.net/?f=P%28A1%5Cbigcap%20B%29%20%3D%20%5Cfrac%7B1%7D%7B2%7D%20%5B%5Cfrac%7B1%7D%7B2%7D%20%5D%5E2%5C%5C%3D%20%5Cfrac%7B1%7D%7B8%7D)
![P(A2\bigcap B) = \frac{1}{2} [\frac{2}{3} ][\frac{1}{3} ]\\=\frac{1}{9}](https://tex.z-dn.net/?f=P%28A2%5Cbigcap%20B%29%20%3D%20%5Cfrac%7B1%7D%7B2%7D%20%5B%5Cfrac%7B2%7D%7B3%7D%20%5D%5B%5Cfrac%7B1%7D%7B3%7D%20%5D%5C%5C%3D%5Cfrac%7B1%7D%7B9%7D)
Prob it is a fair coin = ![\frac{P(A1\bigcap B)}{P(A1\bigcap B)+P(A2\bigcap B)} \\=\frac{\frac{1}{8} }{\frac{1}{8}+\frac{1}{9}} \\=\frac{9}{17}](https://tex.z-dn.net/?f=%5Cfrac%7BP%28A1%5Cbigcap%20B%29%7D%7BP%28A1%5Cbigcap%20B%29%2BP%28A2%5Cbigcap%20B%29%7D%20%5C%5C%3D%5Cfrac%7B%5Cfrac%7B1%7D%7B8%7D%20%7D%7B%5Cfrac%7B1%7D%7B8%7D%2B%5Cfrac%7B1%7D%7B9%7D%7D%20%5C%5C%3D%5Cfrac%7B9%7D%7B17%7D)
I think the answer I d
but I am not good at math