True or False: 2(5m-n) is in simplified form?
2 answers:
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case 1)
Line 1
Let A (2,5) B (-3,-5)
Line 2
Let C (3,0) D (0,-3)
Find the equation of the line 1
Line 1
Let A (2,5) B (-3,-5)
slope m=(y2-y1) /(x2-x1)------> m=(-5-5) /(-3-2)-----> m=2
with m=2 and the point A (2,5) find the equation of the line 1
y-y1=m*(x-x1)------->y-5=2*(x-2)------>y=2x-4+5------> y=2x+1
Find the equation of the line 2
Line 2
Let C (3,0) D (0,-3)
slope m=(y2-y1) /(x2-x1)------> m=(-3-0) /(0-3)-----> m=1
with m=1 and the point C (3,0) find the equation of the line 2
y-y1=m*(x-x1)------->y-0=1*(x-3)------>y=x-3
using a graph tool
see the attached figure N 1
the solution is the point (-4,-7)
case 2)
Line 1
Let A (1,1) B (2,3)
Line 2
Let C (0,3) D (2,5)
Find the equation of the line 1
Line 1
Let A (1,1) B (2,3)
slope m=(y2-y1) /(x2-x1)------> m=(3-1) /(2-1)-----> m=2
with m=2 and the point A (1,1) find the equation of the line 1
y-y1=m*(x-x1)------->y-1=2*(x-1)------>y=2x--2+1------> y=2x-1
Find the equation of the line 2
Line 2
Let C (0,3) D (2,5)
slope m=(y2-y1) /(x2-x1)------> m=(5-3) /(2-0)-----> m=1
with m=1 and the point C (0,3) find the equation of the line 2
y-y1=m*(x-x1)------->y-3=1*(x-0)------>y=x+3
using a graph tool
see the attached figure N 2
the solution is the point (4,7)
case 3)
Line 1
Let A (1,0) B (0,-1)
Line 2
Let C (0,3) D (-2,-1)
Find the equation of the line 1
Line 1
Let A (1,0) B (0,-1)
slope m=(y2-y1) /(x2-x1)------> m=(-1-0) /(0-1)-----> m=1
with m=1 and the point A (1,0) find the equation of the line 1
y-y1=m*(x-x1)------->y-0=1*(x-1)------>y=x-1
Find the equation of the line 2
Line 2
Let C (0,3) D (-2,-1)
slope m=(y2-y1) /(x2-x1)------> m=(-1-3) /(-2-0)-----> m=2
with m=2 and the point C (0,3) find the equation of the line 2
y-y1=m*(x-x1)------->y-3=2*(x-0)------>y=2x+3
using a graph tool
see the attached figure N 3
the solution is the point (-4,-5)
case 4)
Line 1
Let A (2,0) B (0,-2)
Line 2
Let C (4,5) D (3,3)
Find the equation of the line 1
Line 1
Let A (2,0) B (0,-2)
slope m=(y2-y1) /(x2-x1)------> m=(-2-0) /(0-2)-----> m=1
with m=1 and the point A (2,0) find the equation of the line 1
y-y1=m*(x-x1)------->y-0=1*(x-2)------>y=x-2
Find the equation of the line 2
Line 2
Let C (4,5) D (3,3)
slope m=(y2-y1) /(x2-x1)------> m=(3-5) /(3-4)-----> m=2
with m=1 and the point C (4,5) find the equation of the line 2
y-y1=m*(x-x1)------->y-5=2*(x-4)------>y=2x-8+5-----> y=2x-3
using a graph tool
see the attached figure N 4
the solution is the point (1,-1)
