Answer:
65
Step-by-step explanation:
So a number (let's call that x) plus -43 is 22. In an equation:
![x-43=22](https://tex.z-dn.net/?f=x-43%3D22)
To find the number, add 43 to both sides. The left cancels:
![x=65](https://tex.z-dn.net/?f=x%3D65)
And we're done!
Answer:
the mle of P=0.833
Step-by-step explanation:
X=incorrect answer
And probability of success to be denoted as P
Here X posses a binomial distribution along with 'r' and 'p'parameter
CHECK THE ATTACHMENT BELOW FOR DETAILED EXPLATION
Answer:
27/64 or any other equivalent form
Step-by-step explanation:
using quotient rule
![\frac{d}{dx} (\frac{f}{g} )= \frac{f'(g)-g'(f) }{g^2}](https://tex.z-dn.net/?f=%5Cfrac%7Bd%7D%7Bdx%7D%20%28%5Cfrac%7Bf%7D%7Bg%7D%20%29%3D%20%5Cfrac%7Bf%27%28g%29-g%27%28f%29%20%7D%7Bg%5E2%7D)
f'(x) =
= ![\frac{6x+2x^2 -x^2}{(3+x)^2} = \frac{x^2+6x}{(3+x)^2}](https://tex.z-dn.net/?f=%5Cfrac%7B6x%2B2x%5E2%20-x%5E2%7D%7B%283%2Bx%29%5E2%7D%20%3D%20%5Cfrac%7Bx%5E2%2B6x%7D%7B%283%2Bx%29%5E2%7D)
using quotient rule again
f''(x) =
simplifying to make it easier to plug in
f''(x) = ![\frac{(2x+6)(x^2+6x+9)- (6+2x)(x^2+6x)}{(x+3)^4}](https://tex.z-dn.net/?f=%5Cfrac%7B%282x%2B6%29%28x%5E2%2B6x%2B9%29-%20%286%2B2x%29%28x%5E2%2B6x%29%7D%7B%28x%2B3%29%5E4%7D)
= ![\frac{(2x^3+12x^2+18x+6x^2+36x+9)-(6x^2+36x+2x^3+12x^2)}{(x+3)^4}](https://tex.z-dn.net/?f=%5Cfrac%7B%282x%5E3%2B12x%5E2%2B18x%2B6x%5E2%2B36x%2B9%29-%286x%5E2%2B36x%2B2x%5E3%2B12x%5E2%29%7D%7B%28x%2B3%29%5E4%7D)
= ![\frac{2x^3+12x^2+18x+6x^2+36x+9-6x^2-36x-2x^3-12x^2}{(x+3)^4}](https://tex.z-dn.net/?f=%5Cfrac%7B2x%5E3%2B12x%5E2%2B18x%2B6x%5E2%2B36x%2B9-6x%5E2-36x-2x%5E3-12x%5E2%7D%7B%28x%2B3%29%5E4%7D)
= ![\frac{18x+9}{(x+3)^4}](https://tex.z-dn.net/?f=%5Cfrac%7B18x%2B9%7D%7B%28x%2B3%29%5E4%7D)
f''(1) =
= ![\frac{27}{64}](https://tex.z-dn.net/?f=%5Cfrac%7B27%7D%7B64%7D)
Answer:
-11
Step-by-step explanation:
if you put the numbers of the variebles in, it would be
-6-9+9-5