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Nataliya [291]
3 years ago
11

Tan weighs 146 pounds. Minh weighs 15 pounds more than Tan. How much does Minh weigh?

Mathematics
1 answer:
dimaraw [331]3 years ago
3 0

Given parameters:

Weight of Tan  = 146pounds

Unknown:

Weight of Minh = ?

Following this problem step wisely, we can derive a solvable algebraic equation;

  Let the weight of Minh  = M

In the second sentence, we see that Minh weighs 15pounds more than Tan;

    So;

              M  = 15 + Weight of Tan

Since we already know the weight of Tan,

  Weight of Minh  = 15 + 146  = 161pounds

We clearly see that Minh's weight will be 161 pounds.

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Step-by-step explanation:

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The figures below are made out of circles, semicircles, quarter circles, and a square. Find the area and the perimeter of each f
WITCHER [35]

Answer:

Part 1) A=36(\pi-2)\ cm^2

Part 2) P=6(\pi+2\sqrt{2})\ cm

Step-by-step explanation:

<u><em>The picture of the question in the attached figure</em></u>

Part 1) Find the area

we know that

The area of the shape is equal to the area of a quarter of circle minus the area of an isosceles right triangle

so

A=\frac{1}{4}\pi r^{2}-\frac{1}{2}(b)(h)

we have that the base and the height of triangle is equal to the radius of the circle

r=12\ cm\\b=12\ cm\\h=12\ cm

substitute

A=\frac{1}{4}\pi (12)^{2}-\frac{1}{2}(12)(12)\\A=(36\pi-72)\ cm^2

simplify

Factor 36

A=36(\pi-2)\ cm^2

Part 2) Find the perimeter

The perimeter of the figure is equal to the circumference of a quarter of circle plus the hypotenuse of the right triangle

The circumference of a quarter of circle is equal to

C=\frac{1}{4}(2\pi r)=\frac{1}{2}\pi r

substitute the given values

C=\frac{1}{2}\pi (12)\\C=6\pi\ cm

Applying the Pythagorean Theorem

The hypotenuse of right triangle is equal to

AC=\sqrt{12^2+12^2}\\AC=\sqrt{288}\ cm

simplify

AC=12\sqrt{2}\ cm

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P=(6\pi+12\sqrt{2})\ cm

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4 0
3 years ago
Find lim h 0 f(2+h)-f(2)/ h if(x)=x^ 2 .
jonny [76]

Answer:

4

Step-by-step explanation:

6 0
2 years ago
Read 2 more answers
Jenny bought a 5 notebooks and 2 pencils, and the total was 9 dollars.
weeeeeb [17]
You would solve this with simultaneous equations, so if we write it as:
5n + 2p = 9
3n + 2p = 6
(subtract)
2n = 3
÷ 2
notebooks = 1.5

Now you would substitute it in:
(3 × 1.5) + 2p = 6
4.5 + 2p = 6
- 4.5
2p = 1.5
÷ 2
pens = 0.75

So your final answer is notebooks are $1.50 and pens are $0.75, I hope this helps!
6 0
3 years ago
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