Answer:
280000lb
Step-by-step explanation:
In this question, we shall be calculating the amount of carbon iv oxide prevented from entering the atmosphere.
Generally we know that 1kwh produces 1.37 lbs of Carbon iv oxide in the atmosphere
Now, using a 100 watt light bulb daily for 8 hours, for a year, the amount of Carbon iv oxide produced will be;
100 * 1.37 * 8 * 365 = 40040 lb
Using a 30 watt CFL for 8hrs/ day for a year, we have;
30 * 1.37 * 8 * 365 = 120012 lb
Now calculating the amount of CO2 prevented, we have 40040 - 120012 = 280028 lb = 280000 after rounding up
Answer:
m=8
Step-by-step explanation:
-88=-3(4m+5)-(1-3m)
-88=-12m-15-(1-3m) <- Distributive Property
-88=-12m-15-1+3m <- Open () if there is a negative negative the symbol equals positive
-88=-9m-16 <- Simplify
0=-9m+72 <- Add 88 to both sides
9m = 72 <- Add 9m to both sides
9m = 72
/9 /9
m=8
Answer:
5
Step-by-step explanation:
I think the answer was 0.18 but I'm not sure so...yeah
<span><span>(<span>2/3</span>)</span>5</span><span>=<span><span>(<span>2/3</span>)</span>5</span></span><span>=<span><span><span><span><span>(<span>2/3</span>)</span>*<span>(<span>2/3</span>)</span></span>*<span>(<span>2/3</span>)</span></span>*<span>(<span>2/3</span>)</span></span>*<span>(<span>2/3</span>)</span></span></span><span>=<span><span><span><span><span>2*2</span>*2</span>*2</span>*2</span><span><span><span><span>3*3</span>*3</span>*3</span>*3</span></span></span><span>=<span><span>2^5/</span><span>3^5</span></span></span><span>=<span>32/243</span></span><span>(Decimal: 0.131687)</span>
