Answer:
The image of the point (1, -2) under a dilation of 3 is (3, -6).
Step-by-step explanation:
Correct statement is:
<em>What are the coordinates of the image of the point (1, -2) under a dilation of 3 with the origin.</em>
From Linear Algebra we get that dilation of a point with respect to another point is represented by:
(Eq. 1)
Where:
- Reference point with respect to origin, dimensionless.
- Original point with respect to origin, dimensionless.
- Dilation factor, dimensionless.
If we know that 
, 
and 
, then the coordinates of the image of the original point is:
![\vec P' = (0,0) +3\cdot [(1,-2)-(0,0)]](https://tex.z-dn.net/?f=%5Cvec%20P%27%20%3D%20%280%2C0%29%20%2B3%5Ccdot%20%5B%281%2C-2%29-%280%2C0%29%5D)
The image of the point (1, -2) under a dilation of 3 is (3, -6).
Answer:
Janine is 28. Ingrid is 30.
Step-by-step explanation:
Let the ages be x and x + 2 for Janine and her sister, respectively.
x/7 + (x + 2)/3 = 14
Multiply both sides by the LCD, 21, to get rid of denominators.
21 * x/7 + 21 * (x + 2)/2 = 21 * 14
3x + 7(x + 2) = 294
3x + 7x + 14 = 294
10x = 280
x = 28
x + 2 = 30
Answer: Janine is 28. Ingrid is 30.
First round up 249.99 to 250.00
Then change the 4% into a decimal= 1.04
Now multiply so the equation is= 250 x 1.04 =
$260 as your answer!
Https://www.symbolab.com/solver/function-asymptotes-calculator this is a good asymptote calculator
Answer:
0.15
Step-by-step explanation:
I don't know if that is right but sorry if it is wrong but I would check with your teacher or someone for help
