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Marizza181 [45]
3 years ago
8

What is the answer?

Mathematics
1 answer:
Leto [7]3 years ago
3 0
I need more info for this one
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What is the atomic number of an atom?
mariarad [96]

Answer:

The number of protons

Step-by-step explanation:

Its the correct answer

6 0
3 years ago
HELP!!! CORRECT ANSWER NEEDED OR ELSE I FAIL ;-; STUDY ISLAND !!
Ket [755]

Answer:

  B.  Step 2 uses the associative property, and step 3 uses the commutative property.

Step-by-step explanation:

The associative property lets you group terms for addition any way you like. It appears that in Step 2, the grouping is ...

  4 + (1/6 + 3) + 5/6

The commutative property lets you change the order of any pair of terms involved in addition. It appears that in Step 3, the order of the terms within the group has been swapped.

  4 + (3 + 1/6) + 5/6

_____

<em>Comment on associative and commutative properties</em>

What applies to terms in addition applies to factors in multiplication.

5 0
3 years ago
Please help me with these questions.....please...
tatuchka [14]
The first one is A and the second one is B, hope this helps!!
8 0
2 years ago
An atom of chlorine has several valence electrons in its
Vitek1552 [10]
Chlorine atom has 7 electrons in their valence shell
5 0
3 years ago
7. The bottom of a circular swimming pool
mote1985 [20]
<h2>Hello!</h2>

The answer is:

1017.88 square feet are blue.

<h2>Why?</h2>

To calculate how many square feet are blue, we need to calculate the area of the bottom of the circular swimming pool.

We need to remember that we can calculate the area of any circle using the following formula:

Area_{circle}=\pi radius^{2}

Now, we know that the diameter of the bottom is equal to 36 feet, so, we can calculate the radius of the bottom using the following formula:

diameter=2radius\\\\radius=\frac{diameter}{2}

So,

radius=\frac{36feet}{2}=18feet

Then, calculating the area we have:

Area_{bottom}=\pi radius^{2}=\pi 18ft^{2}=1017.88ft^{2}

Hence, we have that 1017.88 square feet are blue.

Have a nice day!

4 0
3 years ago
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