Answer:
The objective function in terms of one number, x is
S(x) = 4x + (12/x)
The values of x and y that minimum the sum are √3 and 4√3 respectively.
Step-by-step explanation:
Two positive numbers, x and y
x × y = 12
xy = 12
S(x,y) = 4x + y
We plan to minimize the sum subject to the constraint (xy = 12)
We can make y the subject of formula in the constraint equation
y = (12/x)
Substituting into the objective function,
S(x,y) = 4x + y
S(x) = 4x + (12/x)
We can then find the minimum.
At minimum point, (dS/dx) = 0 and (d²S/dx²) > 0
(dS/dx) = 4 - (12/x²) = 0
4 - (12/x²) = 0
(12/x²) = 4
4x² = 12
x = √3
y = 12/√3 = 4√3
To just check if this point is truly a minimum
(d²S/dx²) = (24/x³) = (8/√3) > 0 (minimum point)
Answer:
x<-2
Step-by-step explanation:
You first subtract 4 from both sides. Then you divide both sides by -8 (note: when you multiply or divide by a negative the sign flips. Then you get your answer
Step-by-step explanation:
Hey, there!!
Let's simply work with it,
60° + 2x° + (2x+12)° = 180° { being a linear pair}.
or, 72° + 4x = 180°
4x = 180° - 70°
Therefore, the value of x is 27°.
Now,
2x° = (2×27)°= 54°
(2x+12)° = 2×27°+12°= 66°.
(x+2)= 27+ 2= 29°
Now, The left angle is 27°.
Therefore, The answer is option A.
<em><u>Hope</u></em><em><u> </u></em><em><u>it helps</u></em><em><u>.</u></em><em><u>.</u></em><em><u>.</u></em>
You need two terms that multiply to (12x-4). The term on the outside needs to be a common multiple of 12 and 4. The common factors are 1, 2, and 4. Here are the following possible dimensions:
1(12x-4)
2(6x-2)
4(3x-1)
Hope this helps.
