Answer: a) (0.755, 0.925)
Step-by-step explanation:
Let p be the population proportion of 8th graders are involved with some type of after school activity.
As per given , we have
n= 100
sample proportion:
Significance level :
Critical z-value : (using z-value table)
Then, the 98% confidence interval that estimates the proportion of them that are involved in an after school activity will be :-
i.e.
i.e.
i.e.
Hence, the 98% confidence interval that estimates the proportion of them that are involved in an after school activity : a) (0.755, 0.925)
Answer:
Correct option: first one
Step-by-step explanation:
The graph has 3 different parts:
Cost = 15 when the Gigabytes used is lesser than or equal 2,
Cost from 20 to 40 when the Gigabytes used is greater than 2 and lesser than or equal 6.
An increase of 4 gigabytes caused an increase of 20 in the cost, so the slope is 20/4 = 5, and the y-intercept is:
20 = 5*2 + b -> b = 10
Cost = 50 when the Gigabytes used is greater than 6.
So the correct option is the first one
Answer:
No
Step-by-step explanation:
Plug in the x and y values and you should get 3<9
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