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Reil [10]
3 years ago
10

In the expression 1 o 2 o 3 o 4 each o is to be replaced be either + or x.

Mathematics
1 answer:
disa [49]3 years ago
7 0
The answer is e 25 
as 2 time 3 times 4 is 24 plus the 1
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Factorize 5r⁸t⁵ - 3r⁴t⁴​
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Factor r 4 t 4 out of 5 r 8 t 5 − 3 r 4 t 4 . r 4 t 4 ( 5 r 4 t − 3 )

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3 years ago
In the data set below, what is the range? 9, 4, 9, 2, 8, 2, 1
noname [10]
First put these in order from least to greatest.

1,2,2,4,8,9,9 is the correct order
Range is when we subtract the greatest value of our data set from the smallest so in our case it would be 9-1 which leaves us with our answer that 8 is your range.
7 0
3 years ago
For all positive integers n, let *n* equal the greatest prime number that is a divisor of n. What does *10*/*12* equal?
artcher [175]

9514 1404 393

Answer:

  5/3

Step-by-step explanation:

The prime factorizations are ...

  10 = 2·5

  12 = 2·2·3

Then *10* = 5 and *12* = 3, so *10*/*12* = 5/3.

4 0
3 years ago
Question 10: If the product of all the numbers from 1 to 100 is divisible by 2^n, then what is the maximum possible value for n:
Klio2033 [76]

Answer: D

Step-by-step explanation:

100!=2*3*4*...*100

Counting which numbers are divisible by 2:

2,4,6,8,10,12,14,...,96,98,100 : 50 numbers (100/2=50)

Counting which numbers are divisible by 4=2²:

4,8,12,16,20,...96,100: 25 numbers (100/4=25)

Counting which numbers are divisible by 8=2³:

8,16,24,32,40,...,96: 12 numbers (100/8=12.5 ==> 12)

Counting which numbers are divisible by 16=2⁴:

16,32,48,...,96: 6 numbers (100/16=6.25 ==> 6)

Counting which numbers are divisible by 32=2⁵:

32,64,96 : 3 numbers(100/32=3.125 ==>3)

Counting which numbers are divisible by 64=2⁶:

64 : 1 number (100/64=1.5625 ==>1)

Sum of those numbers= 50+25+12+6+3+1=97

100! is divisible by 2⁹⁷.

Answer D

4 0
3 years ago
Read 2 more answers
The scale of a map says that 3cm represents 8km. What distance on the map (in centimeters) represents an actual distance of 2 ki
makvit [3.9K]
X/2=3/8x
x=(2)3/8
x=6/8
x=3/4
x=0.75cm
5 0
3 years ago
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