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Slav-nsk [51]
4 years ago
12

Calculate the average rate of change for the given function, from x = 8 to x = 5.

Mathematics
2 answers:
iren2701 [21]4 years ago
8 0
The answer for the slope is -4/3
kumpel [21]4 years ago
7 0
The average rate of change from x=8 to x=5 can be calculated as:

\frac{f(8)-f(5)}{8-5}

f(8) = 0
f(5) = 4

Using the values we get:

\frac{0-4}{8-5} \\  \\ 
 -\frac{4}{3}

So, first option gives the correct average rate of change from x=8 to x =5 for the given function.
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What is the 13th square number?​
Sholpan [36]

Answer:

169

Step-by-step explanation:

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4 0
3 years ago
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Do the following pairs correspond to a function
wel
Yes it is a function 


6 0
4 years ago
Can someone please help me with that ? So confused
nasty-shy [4]
That's what it will look like

7 0
3 years ago
8,699 rounded to the nearest ten
aleksley [76]
Ok so first You look at the number:8,699. Where's the Tens place?  The tens place is easy to find by using expanded notation......8,000 + 600 + 90 + 9.
90 is the tens place you see? So in order to answer this right,You keep Every number on the right side of 90 and add it to 90 So.......90+9 = 99 .

99 is the area you going to round. In order to round you look at the one place
(the 9) and and see if its a number bigger than the number 5 which it is!
so read this.........4 or below let it go,5 or above give it a shove.  So because it bigger than 5 you round it up. so.......8,6(99) rounded up would be simple.....

99 goes up so 90 (the tens place) goes to 100.  BUT 8,6100 is wrong and you should now that so just do this.

99 turned to 100 so 600 (Hundreds place)  + 100 (tens place rounded) = 700

Answer to this Number 8,700
5 0
4 years ago
18. The desired density of the shaved ice is 0.697 g/cm3, and the cost, per kilogram, of ice is $3,83. Determine
Ostrovityanka [42]

The cost of the ice needed to make 50 snow cones is $54.50.

<h3>What is cost of the ice?</h3>

The first step is to determine the volume of the snow cone.

Volume of the snow cone =volume of a cone + volume of the hemisphere

Volume of the cone = 1/3πr²h

1/3 x 3.14 x 10.2 x (8.3/2)² = 183.87 cm³

Volume of the hemisphere = 2/3πr³

2/3 x 3.14 x (8.3 / 2)³ = 224.43 cm³

Total volume = 224.43 cm³ + 183.87 cm³ = 408.30 cm³

Volume of 50 snow cones =  408.30 cm³ x 50 = 20,414.82

Total grams of ice needed = density x volume

0.697 x 20,414.82 = 14,229.13 grams

Convert gram to 1kg

1kg = 1000g

= 14,229.13 grams  / 1000 = 14.23kg

Cost of the ice = 14.13 x 3.83 = $54.50

Please find attached the image of the snow cone. To learn more about the volume of a cone, please check: brainly.com/question/13705125

#SPJ1

8 0
2 years ago
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