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RideAnS [48]
3 years ago
14

Help me please. . . .

Biology
1 answer:
kodGreya [7K]3 years ago
3 0
Number 1 ,3 and 4 are the answers


good luck
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In tomatoes, a heterozygous plant with normal fruit and purple stems is crossed with a recessive plant having fasciated fruit an
Pani-rosa [81]

Answer:

Recombination frequency, P = 0.23.

If the recombination frequency is < 50%, genes are linked. A RF of 23% tells us that these two genes are in the same chromosome, close enough to be linked.

  • 1% of recombinations = 1 map unit
  • 23% = 23 map units

The genes for stem color and fruit type seem to be in the same chromosome, linked and 23 MP apart.

Explanation:        

In the present example, the genes for stem color and fruit type seem to be linked.

To know if two genes are linked, we must observe the progeny distribution. If individuals, whos genes assort independently, are test crossed, they produce a progeny with equal phenotypic frequencies 1:1:1:1. If we observe a different distribution, that is that phenotypes appear in different proportions, we can assume that genes are linked in the double heterozygote parent.  

In this way, we might verify which are the recombinant gametes produced by the di-hybrid, and we will be able to recognize them by looking at the phenotypes with <u>lower frequencies in the progeny</u><u>.</u>    

The following distribution of offspring is observed:

  • normal fruit, purple stems 38.5%
  • fasciated fruit green stems 38.5%
  • normal fruit, green stems 11.5%
  • fasciated fruit, purple stems 11.5%

38.5% + 38.5% + 11.5% + 11.5% = 100%

N (total number of individuals in the progeny) = 100

  • number of individuals with normal fruit, purple stems 38.5
  • number of individuals with fasciated fruit green stems 38.5
  • number of individuals with normal fruit, green stems 11.5
  • number of individuals with fasciated fruit, purple stems 11.5

To calculate the recombination frequency we will make use of the next formula: P = Recombinant number / Total of individuals. The genetic distance will result from multiplying that frequency by 100 and expressing it in map units (MU).

P = Recombinant number / Total of individuals.

P = 11.5 + 11.5 / 100

P = 0.23  

We need to know that 1% of recombinations = 1 map unit = 1cm. Also, the maximum recombination frequency is always 50%.  This means that if the recombination frequency is < 50%, genes are linked. A RF of 23% tells us that these two genes are in the same chromosome, close enough to be linked. FR 23% = 23 UM.  

 

6 0
2 years ago
HELPPPPPPPP FASTTTTTTTTTTT NOWWWWW
Kruka [31]

Answer:

T

A

C

C

C

G

A

T

G

A

T

C

Explanation:

Each base is paired as follows in DNA:

A paired with T

T paired with A

C paired with G

G paired with C

The letters refer to the primary nucleic acid bases: adenine, cytosine, guanine, and thymine.

b) mRNA strand:

A

U

G

G

G

C

U

A

C

U

A

G

c) Amino Acid Table below! Remember to start from the 5' end of mRNA (toward the 3' end) at a 'start codon'. So read through until you find a group of 3 that make up a start codon, then end with a 'stop codon'. I have to go take a final exam, but you got this!!!

4 0
2 years ago
A person who is homozygous for the x chromosome is
xxMikexx [17]
A person who is homozygous for the X chromosome is female.
Women have two X chromosomes, which means they are homozygous for the X chromosome - the word homozygous means that they have 'two chromosomes of the same kind.' Men have different types of chromosomes - XY. 

7 0
3 years ago
Suppose a mass of very cold air hits a mass of air that is very warm and wet. What will most likely happen?
tensa zangetsu [6.8K]

They can also merge in what’s known as an occluded front, an important stage in the development of many of the great weather-making low-pressure systems known as midlatitude cyclones.

8 0
3 years ago
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The ventral cerebral peduncles are contained in the
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<span>Midbrain also called the mesencephalon</span>
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