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3 years ago

What is y = x+ 3 on a graph look like?

Mathematics

1 answer:

balandron [24]3 years ago

6 0

Answer:

(shown in picture)

Step-by-step explanation:

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Solve this inequality 2(4x-3)≥-3(3x)+5x?

Y_Kistochka [10]

The first option, x is greater than and equals to 0.5

7 0

4 years ago

Read 2 more answers

If aa skateboard ramp is 15 meters long and it extends 12 meters from the base of the starting point. How high is the ramp?

guapka [62]

The height of the ramp is 9 meter

<u>Solution:</u>

It is given that a skateboard ramp is 15 meters long and it extends 12 meters from the base of the starting point.

If we look at the sum, closely we understand that the ramp is a right angled triangle.

Which has a base length of 12 metres and a hypotenuse of 15 metres.

We need to find its height.

To do so we can use the Pythagoras theorem

Pythagorean theorem, states that the square of the length of the hypotenuse is equal to the sum of squares of the lengths of other two sides of the right-angled triangle.

By above definition, we get

$\text {Hypotenuse}^{2}=\text {height}^{2}+\text { base }^{2}$

Since we already know the lengths of the hypotenuse and base we can substitute them in the formula and solve for the height.

Let height of the ramp be denoted by ‘h’

$\begin{array}{l}{15^{2}=12^{2}+h^{2}} \\\\ {225=144+h^{2}} \\\\ {225-144=h^{2}} \\\\ {81=h^{2}} \\\\ {h=\sqrt{81}} \\\\ {h=9}\end{array}$

Therefore, the height of the ramp is 9 meter

3 0

3 years ago

What is the radius of a circle whose equation is X^2 plus Y^2 -10X +6 X +18=0?

frosja888 [35]

ANSWER

The radius is 4

EXPLANATION

The given equation is:

${x}^{2} + {y}^{2} - 10y + 6x + 18 = 0$

We complete the square to get the expression in standard form:

${x}^{2} + 6x + {y}^{2} - 10y + 18 = 0$

${x}^{2} + 6x + 9 + {y}^{2} - 10y + 25 = - 18 + 9 + 25$

We factor using perfect squares to get:

${(x + 3)}^{2} + {(y - 5)}^{2} = 16$

This implies that,

${(x + 3)}^{2} + {(y - 5)}^{2} = {4}^{2}$

Comparing to

${(x - h)}^{2} + {(y - k)}^{2} = {r}^{2}$

The radius is r=4

3 0

3 years ago

Identify the domain of the function shown in the graph.

Klio2033 [76]

Step-by-step explanation:

The domain of the function is the range of x-values, which is -5 <= x <= 5. (D)

5 0

3 years ago

A point P is moving along the curve whose equation is y = \sqrt x . Suppose that x is increasing at the rate of 4 units/s when x

Mice21 [21]

Answer:3 units/s

Step-by-step explanation:

Given

$y=\sqrt{x}$

Point P lie on this curve so any general point on curve can be written as $(x,\sqrt{x})$

and $\frac{\mathrm{d} x}{\mathrm{d} t}=4 units/s$

Distance between Point P and (2,0)

$P=\sqrt{(x-2)^2+(\sqrt{x}-0)^2}$

P at x=3 P=2

rate at which distance is changing is

$\frac{\mathrm{d} P}{\mathrm{d} t}=\frac{\mathrm{d} \sqrt{(x-2)^2+(\sqrt{x}-0)^2}}{\mathrm{d} t}$

$\frac{\mathrm{d} P}{\mathrm{d} t}=\frac{2x-3}{\sqrt{(x-2)^2+(\sqrt{x}-0)^2}}\times \frac{\mathrm{d} x}{\mathrm{d} t}$

$\frac{\mathrm{d} P}{\mathrm{d} t}=\frac{2\times 3-3}{2\times 2}\times 4=3 units/s$

8 0

3 years ago