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2 years ago

Which graph shows the new position of the rectangle after a translation?

Mathematics

1 answer:

mel-nik [20]2 years ago

7 0

3rd image. translations are rigid transformations that do not change the orientation of the original image. 2and 4 are rotations and 5 is a dilation.

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The graph of y=sin is stretched vertically by a factor of 3 , compressed horizontally by a factor of 6 (angular frequency of 6),

SVEN [57.7K]

Answer:

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Step-by-step explanation:

5 0

2 years ago

Read 2 more answers

Which of the following could be the graph of the equation y = -2x? *<br> please answer

mihalych1998 [28]

B.

The line starts at the origin and goes down by two.

6 0

2 years ago

5 (2x + 10) = 50<br> What is the answer

KATRIN_1 [288]

9514 1404 393

Answer:

x = 0

Step-by-step explanation:

You can eliminate parentheses and subtract 50.

5(2x +10) = 50

10x +50 = 50 . . . . use the distributive property

10x = 0 . . . . . . . . . subtract 50 from both sides

x = 0 . . . . . . . . . . . divide by 10

<em>Check</em>

5(2·0 +10) = 50

5(10) = 50 . . . . true

5 0

2 years ago

If the perimeter of an isosceles trapezoid is 79.53 meters, and the bases measure 25.62 meters and 33.51 meters, find the length

elixir [45]

An isosceles trapezoid is one that has 2 bases of different lengths and the other 2 sides having the same length as each other (definition of isosceles trapezoid). So if the perimeter is 79.53, the the formula is 79.53=x+x+25.62+33.51 and 79.53=2x+59.13. Solve that for x to get that x=10.2. That's your answer! Each leg is 10.2 meters long.

3 0

3 years ago

(a^2 - b^2)/(2 + d^3)

Georgia [21]

Answer:

Solving the equation $\frac{a^2-b^2}{2+d^3}$ by putting a=6, b=4 and d=1/2 we get $\frac{160}{17}$

Step-by-step explanation:

We are given formula: $\frac{a^2-b^2}{2+d^3}$

and values a=6, b=4 and d=1/2

We need to put the values of a, b and d in the given equation $\frac{a^2-b^2}{2+d^3}$ and find their result

Putting values in the equation:

$\frac{a^2-b^2}{2+d^3}\\=\frac{(6)^2-(4)^2}{2+(\frac{1}{2})^3}\\=\frac{36-16}{2+\frac{1}{8}}\\=\frac{20}{\frac{2*8+1}{8}}\\=\frac{20}{\frac{17}{8}}\\=\frac{20*8}{17}\\=\frac{160}{17}$

So, solving the equation $\frac{a^2-b^2}{2+d^3}$ by putting a=6, b=4 and d=1/2 we get $\frac{160}{17}$

7 0

3 years ago