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Mrrafil [7]
4 years ago
14

On Fridays at the ballpark, a cup of soda costs $3, and each refill costs $0.60. If x represents the number of refills, which of

the following equations represents the amount a person spends on soda?
Mathematics
2 answers:
KiRa [710]4 years ago
7 0
In order to make an equation for the sodas, We first need to look at what we know. We know that a cup of soda initially costs $3. Now we know that our variable x is .60.

We now have to put it into an equation where 3 is a solid term while .60 can change. This then can be represented by:

.60x+3=y 
Y is your total that a person spends on soda. 

8090 [49]4 years ago
7 0
Keeping in mind the end goal to make a condition for the soft drinks, We initially need to take a gander at what we know. We realize that a measure of pop at first expenses $3. Presently we realize that our variable x is .60. 
now you need to place it into a condition where 3 is a strong term while .60 can change.

60x+3=y.
Y is your aggregate that a man spends on pop.
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3 years ago
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Alenkinab [10]
<h2>Answer:</h2>

y=\pm (\frac{x}{6})^{\frac{1}{4}} \ is \ not \ a \ function

<h2>Step by step solution:</h2>

A function f from a set A to a set B is a relation that assigns to each element x in the set A exactly one element y in the set B. The set A is the domain (also called the set of inputs) of the function and the set B contains the range (also called the set of outputs). On the other hand, a function has an inverse function if and only if passes the Horizontal Line Test for Inverse Functions. This test tells us that a function f has an inverse function if and only if there is no any horizontal line that intersects the graph of f at more than one point. So the function is called one-to-one. The graph of f is shown below. As you can see, this function does not pass the Horizontal Line Test, therefore the inverse is not a function. However, let's find f^-{1}(x):

f(x)=6x^4 \\ \\ Substitute \ f(x) \ by \ y \\ \\ y=6x^4 \\ \\ Interchange \ x \ and \ y: \\ \\ x=6y^4 \\ \\ Solve \ for \ y: \\ \\ y^4=\frac{x}{6} \\ \\ Solving \\ \\y=\pm \sqrt[4]{\frac{x}{6}} \\ \\ \boxed{y=\pm \left(\frac{x}{6}\right)^{\frac{1}{4}}}

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