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3 years ago

15

Plot a point at the y-intercept pf the following function on the graph provided. 3y= -5^x+7

1 answer:

Brums [2.3K]3 years ago

4 0

Answer:

y-intercept: (0, 2)

Step-by-step explanation:

By graphing the equation into a graphing calc, you can trace the graph to where the y-int is located and you have your answer of (0, 2)

<em>Alternatively, </em>you could set x equal to zero and solve algebraically to find the y-int. However, if you are under a time crunch, graphing will be the faster way to go.

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Help please triangles and trig

Oksanka [162]

Answer:

$\sin L = \frac{3}{5}$

$\tan N = \frac{4}{3}$

$\cos L = \frac{4}{5}$

$\sin N = \frac{4}{5}$

Step-by-step explanation:

Given

The above triangle

First, we calculate the length LM using Pythagoras theorem.

$LN^2 = LM^2 + MN^2$

$10^2 = LM^2 + 6^2$

$100 = LM^2 + 36$

Collect like terms

$LM^2 = 100 - 36$

$LM^2 = 64$

Take positive square root

$LM=8$

Solving (a): Sin L

$\sin L = \frac{Opposite}{Hypotenuse}$

$\sin L = \frac{MN}{LN}$

$\sin L = \frac{6}{10}$

Simplify

$\sin L = \frac{3}{5}$

Solving (b): tan N

$\tan N = \frac{Opposite}{Adjacent}$

$\tan N = \frac{LM}{MN}$

$\tan N = \frac{8}{6}$

Simplify

$\tan N = \frac{4}{3}$

Solving (c): cos L

This calculated as:

$\cos L = \frac{Adjacent}{Hypotenuse}$

$\cos L = \frac{LM}{LN}$

$\cos L = \frac{8}{10}$

Simplify

$\cos L = \frac{4}{5}$

Solving (d): sin N

This is calculated using:

If $a + b = 90$

Then: $\sin a = \cos b$

So:

$\sin N = \cos L$

$\sin N = \frac{4}{5}$

8 0

3 years ago

So, the area <br> Find the area of the figure of

ch4aika [34]

Answer:

The area of the figure is 117m²

Step-by-step explanation:

In this problem, you have two shapes. One shape is a rectangle. The other shape is a triangle.

Area of a rectangle = b*h = 9*7 = 63

Area of a triangle = $\frac{1}{2}$ (b*h) =

Since there are two triangles, you will multiply the area of the one triangle in the figure by 2.

27*2 = 54

Now, you add up the areas!

54 + 63 = 117

So, the area of the figure is 117m²

7 0

4 years ago

Read 2 more answers

~ ! ANGLE MEASURE ! ~

Troyanec [42]

Answer:

1 and5

Step-by-step explanation:

.......?...........

6 0

3 years ago

A catering company prepared and served 300 meals at an anniversary celebration last week using eight workers. The week before, s

swat32

Answer:

II case.

Step-by-step explanation:

Given that a catering company prepared and served 300 meals at an anniversary celebration last week using eight workers.

The week before, six workers prepared and served 240 meals at a wedding reception.

Productivity is normally measured by number of outputs/number of inputs

Here we can measure productivity as

no of meals served/no of workers

In the I case productivity = $\frac{300}{8} \\=37.5$

In the II case productivity = $\frac{240}{6} \\=40$

Obviously II case productivity is more as per worker 40 meals were served which is more than 37.5 meals per worker in the I case.

3 0

3 years ago

Please help :) I have no clue & math isn’t my strong subject.

melisa1 [442]

Equation of a line that is perpendicular to given line is $y=\frac{-7}{4} x+\frac{7}{4}$ .

Equation of a line that is parallel to given line is $y=\frac{4}{7} x-\frac{69}{7}$ .

Solution:

Given line $y=\frac{4}{7} x+4$ .

Slope of this line, $m_1$ = $\frac{4}{7}$

$$\text{Slope of perpendicular line} = \frac{-1}{\text{Slope of the given line} }$

$$m_2=\frac{-1}{m_1}$

$$=\frac{-1}{\frac{4}{7} }$

Slope of perpendicular line, $m_2=\frac{-7}{4}$

Passes through the point (–7, 5). Here $x_1=-7, y_1=5$ .

Point-slope formula:

$y-y_1=m(x-x_1)$

$$y-(-7)=\frac{-7}{4} (x-5)$

$$y+7=\frac{-7}{4} x+\frac{35}{4}$

Subtract 7 from both sides, we get

$$y=\frac{-7}{4} x+\frac{7}{4}$

Equation of a line that is perpendicular to given line is $y=\frac{-7}{4} x+\frac{7}{4}$ .

To find the parallel line:

Slopes of parallel lines are equal.

$m_1=m_3$

$$m_3=\frac{4}{7}$

Passes through the point (–7, 5). Here $x_1=-7, y_1=5$ .

Point-slope formula:

$$y-(-7)=\frac{4}{7} (x-5)$

$$y+7=\frac{4}{7} x-\frac{20}{7}$

Subtract 7 from both sides,

$$y=\frac{4}{7} x-\frac{69}{7}$

Equation of a line that is parallel to given line is $y=\frac{4}{7} x-\frac{69}{7}$ .

7 0

3 years ago