Answer:
89percent
Step-by-step explanation:
i am not good at math but what ever
Answer:
fourth one
Step-by-step explanation:
Answer:
1995.26
Step-by-step explanation:
It usually works to follow instructions:
3.3 = log(x) . . . . . substitute known values into the equation
10^3.3 = x . . . . . take antilogs
1995.26 = x . . . . simplify, round to hundredths
Let M=macaws lifespan and D=dogs lifespan
M=5D
70=5D
If you want to know the dogs average lifespan then solve for D which is 14years.
Answer:
the numerical value of the correlation between percent of classes attended and grade index is r = 0.4
Step-by-step explanation:
Given the data in the question;
we know that;
the coefficient of determination is r²
while the correlation coefficient is defined as r = √(r²)
The coefficient of determination tells us the percentage of the variation in y by the corresponding variation in x.
Now, given that class attendance explained 16% of the variation in grade index among the students.
so
coefficient of determination is r² = 16%
The correlation coefficient between percent of classes attended and grade index will be;
r = √(r²)
r = √( 16% )
r = √( 0.16 )
r = 0.4
Therefore, the numerical value of the correlation between percent of classes attended and grade index is r = 0.4