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vesna_86 [32]
4 years ago
14

Why dont we use words like prove or does not prove in science

Chemistry
1 answer:
Vera_Pavlovna [14]4 years ago
5 0
You use these words because it is important to use strong words, not 2 year old words. Also, what other words would you use?
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What happens when an electron absorbs energy?
kiruha [24]

Answer:

When an electron absorbs energy, it will move up from a lower energy level to a higher energy level, called the "excited state" of the negatively-charged subatomic particle.

8 0
4 years ago
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Name the types of polymerization and the differences​
Talja [164]
Condensation polymerization : releasing water as by product, occurs in monomer that has functional group that can react with each other e.g alcohol&carboxlic acid to form polyesters, carboxylic acid and amines to form polyamides,etc.

Radical Polymerization: occurs by propagating radical monomers or monomer that has unsaturated bonds, such as ethene, initiated by formation of radical from the monomer by using uv lights/other initiator, does not produce any by products
3 0
3 years ago
The value of ksp for silver sulfide, ag2s, is 8.00×10−51. calculate the solubility of ag2s in grams per liter.
Ivanshal [37]
When Ag₂S dissolves, it dissociates as follows;
Ag₂S ---> 2Ag⁺ + S²⁻
First we need to calculate molar solubility which gives the number of moles dissolved in 1 L of solution.
If molar solubility of Ag₂S is y, then molar solubility of Ag²⁺ and S²⁻ is 2y and y respectively.
ksp gives the solubility constant
ksp = [Ag⁺]²[S²⁻]
ksp = [2y]²[y]
4y³ = 8.00 x 10⁻⁵¹ 
y³ = 2 x 10⁻⁵¹
y = 1.26 x 10⁻¹⁷ mol/L
molar mass = 247.8 g/mol
solubility of Ag₂S = 1.26 x 10⁻¹⁷ mol/L x 247.8 g/mol = 3.12 x 10⁻¹⁵ g/L 
Solubility of Ag₂S = 3.12 x 10⁻¹⁵ g/L 
7 0
4 years ago
Read 2 more answers
If δh = -70.0 kj and δs = -0.300 kj/k , the reaction is spontaneous below a certain temperature. calculate that temperature.
IgorC [24]
The  temperature  for  the  reaction  is  calculated  as  follows

delta  H/ delta S


delta  H=-70 Kj
delta  S  =-0.300  kj/k
temperature  is  therefore = -70kj/-0.300kj/k  =233.33 K
5 0
4 years ago
Read 2 more answers
For a particular reaction, Δ H ∘ = 55.4 kJ ΔH∘=55.4 kJ and Δ S ∘ = 94.1 J/K. ΔS∘=94.1 J/K. Assuming these values change very lit
nadezda [96]

Answer:

The temperature at which the reaction changes from non-spontaneous to spontaneous is 588.735 K

Explanation:

The spontaneity of a reaction is determined by the change in Gibbs Free Energy, \Delta G^{0}.

\Delta G^{0} =\Delta H^{0} -T\Delta S^{0}

If \Delta G^{0} is greater than zero, then a reaction is feasible.

If \Delta G^{0} is less than zero, then a reaction is not feasible.

To determine the temperature at which the reaction changes from non-spontaneous to spontaneous, we should equate the \Delta G^{0} to zero.

We take \Delta G^{0}=0 as the limiting condition.

T=\frac{\Delta H^{0}}{\Delta S^{0}}=\frac{55.4\times10^{3}}{94.1}=588.735K

Therefore, the temperature is: 588.735K

7 0
4 years ago
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